The lengths of time (in years) it took a random sample of 32 former smokers to quit smoking permanently are listed. Assume the population standard deviation is 5.3 years. At a=D0.1, is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years? Complete parts (a) through (e). 7.7 22.1 8.8 18.7 8.2 8.2 10.5 D 11.9 22.5 13.9 13.5 15.3 9.4 20.6 7.2 21.8 20.5 8.7 16.2 13.3 20.9 13.4 13.5 7.4 16.9 17.9 18.4 10.1 11.3 9.2 13.8 19.9 ..... (a) Identify the claim and state the null hypothesis and alternative hypothesis. OA. Ho us13 (claim) ΟΒ. H μ> 13 Ho: H= 13 (claim) H u# 13 Ha: u> 13 Ha: us 13 (claim) O D. Ho: u213 (claim) H3 u<13 OE. Ho: H> 13 (claim) Ho: u 13 (claim) Ha: us 13 H3: µ = 13 (b) Identify the standardized test statistic. Use technology. =| | (Round to two decimal places as needed.)

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### Statistical Analysis: Hypothesis Testing

The task involves analyzing the time (in years) it takes a sample of former smokers to quit smoking permanently. A random sample of 32 individuals is considered. The known population standard deviation is 5.3 years. At a significance level of α = 0.1, we need to determine if there is enough evidence to reject the claim that the mean time to quit smoking is 13 years.

#### Data Sample
Here are the recorded times (in years) for the sample:

```
7.7, 22.1, 8.8, 8.2, 11.9, 8.2, 10.5,
22.5, 13.9, 15.3, 9.4, 20.6, 7.2, 21.8,
20.9, 13.4, 13.5, 7.4, 16.9, 17.9, 18.4,
11.3, 9.2, 13.8, 19.9
```

(Note: Only 25 data points are visible; ensure all 32 are considered in calculations.)

#### Hypothesis Formulation
- **Null Hypothesis (H₀):** μ = 13 (The claim)
- **Alternative Hypothesis (Hₐ):** μ ≠ 13

Options for the hypotheses were provided, and option **C** is selected as it correctly matches the claim.

#### Calculation of Test Statistic
Using technology (e.g., statistical software or a calculator), compute the standardized test statistic, \( z \), rounding to two decimal places as necessary.

#### Instructions
- **Help options:** Assistance provided by step-by-step guidance or examples.
- **Additional tools:** Viewing examples or getting more help for further understanding.
- **Result Verification:** Once calculations are completed, checking the answer ensures validity.

_Copyright © 2021 Pearson Education Inc._
Transcribed Image Text:### Statistical Analysis: Hypothesis Testing The task involves analyzing the time (in years) it takes a sample of former smokers to quit smoking permanently. A random sample of 32 individuals is considered. The known population standard deviation is 5.3 years. At a significance level of α = 0.1, we need to determine if there is enough evidence to reject the claim that the mean time to quit smoking is 13 years. #### Data Sample Here are the recorded times (in years) for the sample: ``` 7.7, 22.1, 8.8, 8.2, 11.9, 8.2, 10.5, 22.5, 13.9, 15.3, 9.4, 20.6, 7.2, 21.8, 20.9, 13.4, 13.5, 7.4, 16.9, 17.9, 18.4, 11.3, 9.2, 13.8, 19.9 ``` (Note: Only 25 data points are visible; ensure all 32 are considered in calculations.) #### Hypothesis Formulation - **Null Hypothesis (H₀):** μ = 13 (The claim) - **Alternative Hypothesis (Hₐ):** μ ≠ 13 Options for the hypotheses were provided, and option **C** is selected as it correctly matches the claim. #### Calculation of Test Statistic Using technology (e.g., statistical software or a calculator), compute the standardized test statistic, \( z \), rounding to two decimal places as necessary. #### Instructions - **Help options:** Assistance provided by step-by-step guidance or examples. - **Additional tools:** Viewing examples or getting more help for further understanding. - **Result Verification:** Once calculations are completed, checking the answer ensures validity. _Copyright © 2021 Pearson Education Inc._
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