Sleeping outlier: A simple random sample of ten college freshmen were asked how many hours of sleep they typically got per night. The results were24 86.56 98.5 7.56.5 8.5 9.5Send data to ExcelNotice that one joker said that he sleeps 24 a day.Part 1 of 3(a) The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 95% confidence interval for the mean amount of sleep fromthe remaining values. Round the answers to at least two decimal places.A 95% confidence interval for the mean amount of sleep from the remaining values is 6.83 <μ< 8.72Part: 1/3Part 2 of 3(b) Leave the outlier in and construct the 95% confidence interval. Round the answers to at least two decimal places.If the outlier is included the 95% confidence interval isVFWX

From the provided information, Sample size (n) = 10 (leaving the outlier in) Confidence level = 95%

Answered: Sleeping outlier: A simple random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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10)The superintendent of a golf course believes that the mean score for professional golfers on his course is above 72. He randomly samples the scores of 40 professional golfers from the last tournament. Here are the scores. 69 67 69 71 75 78 70 71 72 74 72 76 69 76 70 77 78 79 72 71 75 75 75 78 71 64 71 68 72 71 73 72 73 71 71 75 72 72 78 75 Construct a 95% confidence interval for the mean score for all professional golfers on this course. (note: ∑xi=∑xi= 2908, ∑x2=∑x2= 211,850)
A university planner wants to determine the proportion of undergraduate students who plan to attend graduate school. She surveys 54 current students and finds that 27 would like to continue their education in graduate school. Which of the following is the correct 90% confidence interval estimate for the proportion of undergraduates who plan to attend graduate school?
A 95% confidence interval is constructed in order to estimate the proportion of adults who own an iPhone. The resulting interval has a margin of error of 0.043. Which of the following would be the margin of error for a 90% confidence interval based on the same sample of data?
A Pew Internet Project Data Memo presented data comparing adult gamers with teen gamers with respect to the devices on which they play. The data are from two surveys. The adult survey had 1063 gamers, while the teen survey had 1064 gamers. The memo reports that 54% of adult gamers played on game consoles (Xbox, PlayStation, Wii, etc.), while 89% of teen gamers played on game consoles. Suppose you want to construct a 95% confidence interval for the difference. You want to test were or not the two proportions (adult using consoles vs teens using consoles) are the same. You have to calculate a pooled estimate for the proportion. What would that be? (Please round to three decimal places)
2) A random sample of 120 students at a high school was asked whether they would ask their father or mother for help with a homework assignment in science. A second random sample of 150 different students was asked the same question for an assignment in history. Fifty-four students in the first sample and 72 students in the second sample replied that they turned to their mother rather than their father for help. Construct a 99% confidence interval for the difference of the two proportions and express it as . (Round both numbers to the 4th decimal plac
Eric randomly surveyed 150 adults from a certain city and asked which team in a contest they were rooting for, either North High School or South High School. From the results of his survey, Eric obtained the following 95% confidence interval for the proportion of all adults in the city rooting for North High, (0.52,0.68). Interpret this confidence interval. A.We are 95% sure that between 52% and 68% of all adults in this city will root for North High School.B.We are 95% sure that between 52% and 68% of adults in this sample will root for North High School.C.There's a 95% chance that between 52% and 98% of all adults in this city will root for North High School.D.Between 52% and 68% of adults in this city will root for North High School 95% of the time.
The New York Times conducted a nationwide poll of 1048 randomly selected 13- to 17-year-olds. to estimate the proportion of 13- to 17-year-olds who have a television in their room. We can consider the sample to be a simple random sample. Of these 1048 teenagers, 692 had a television in their room. Give a 95% confidence interval for the proportion of all people in this age group who had a TV in their room at the time of the poll, and interpret what your interval means in context. State: Plan: Do: Conclude:
In a poll, 1100 adults in Nantucket were asked about their computer gaming habits. One finding was that 43% of respondents never computer game. Find and interpret a 95% confidence interval for the proportion of all adults in Nantucket who never play computer games
People love living in California for many reasons, but traffic isn’t one of them. Based on a random sample of 572 employed California adults, a 90% confidence interval for the average travel time to work for all employed California adults is 23 minutes to 26 minutes. a. Interpret the confidence level. b. Name two things you could do to reduce the margin of error. What drawbacks do these actions have? c. Describe how nonresponse might lead to bias in this survey. Does the stated margin of error account for this possible bias?
15. Pain after surgery: In a random sample of 50 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 90 patients undergoing a new procedure, only 16 required pain medication. a. Construct a 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. b. A physician claims that the proportion of patients who need pain medication is the same for both procedures. Does the confidence interval contradict this claim? 16
For a study on the current trend in the design of social robots, researchers obtained a random sample of 103 social robots through a Web search and determined that 63 were designed with legs, but no wheels. Complete parts a and b. a. Find a 90% confidence interval for the proportion of all social robots designed with legs, but no wheels. Interpret the result.
Debbie and Ethan are going to construct confidence intervals from the same simple random sample. Debbie's confidence interval will have a 98% confidence interval and Ethan's will have a 95% confidence interval. A. Which confidence interval, if there is a difference will have a larger margin of error? B. Which confidence interval is more likely to cover the population mean, if there is a difference I am using a Ti84 and need to know how to get the answer.

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