Sleeping outlier: A simple random sample of ten college freshmen were asked how many hours of sleep they typically got per night. The results were24 86.56 98.5 7.56.5 8.5 9.5Send data to ExcelNotice that one joker said that he sleeps 24 a day.Part 1 of 3(a) The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 95% confidence interval for the mean amount of sleep fromthe remaining values. Round the answers to at least two decimal places.A 95% confidence interval for the mean amount of sleep from the remaining values is 6.83 <μ< 8.72Part: 1/3Part 2 of 3(b) Leave the outlier in and construct the 95% confidence interval. Round the answers to at least two decimal places.If the outlier is included the 95% confidence interval isVFWX

From the provided information, Sample size (n) = 10 (leaving the outlier in) Confidence level = 95%

Answered: Sleeping outlier: A simple random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Refer to the following scenario. An epidemiologist is worried about the prevalence of the flu in East Vancouver and the potential shortage of vaccines for the area. She will need to provide a recommendation for how to allocate the vaccines appropriately across the city. She takes a simple random sample of 339 people living in East Vancouver and finds that 33 have recently had the flu. Suppose that the epidemiologist wants to re-estimate the population proportion and wishes for her 95% confidence interval to have a margin of error no larger than 0.04. How large a sample should she take to achieve this? Sample size=?
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In a past presidential election, 37,979,113 people voted for Candidate A 37,758,117 for Candidate B; and 206,521 for third-party candidates. a. What percentage of voters chose Candidate A? b. Would it be appropriate to find a confidence interval of voters choosing Candidate A? Why or why not?
.3 The width of a confidence interval is a measure of its precision. The narrower the confidence interval, the more precise is the interval estimate, and vice versa. Describe any three aspects that influence the precision of the width of a confidence interval of a singlepopulation mean.
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Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
You sample 1O0 people to see if they have been to the grocery store in the past week, and find that 85% (.85) of them have been. What is the 95% confidence interval for this study? Leave your answer in decimal format to 2 decimal places. In other words, .04 instead of 3.6% or .11 instead of 11.4%.. O .78 to .92 .84 to .85 O .60 to 1.10 O .60 to 1.00 .15 to 1.55
15. Pain after surgery: In a random sample of 50 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 90 patients undergoing a new procedure, only 16 required pain medication. a. Construct a 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. b. A physician claims that the proportion of patients who need pain medication is the same for both procedures. Does the confidence interval contradict this claim? 16
A 95% confidence interval for how much time on average GRC students spend doing homework every day is 75 to 105 minutes.Choose a correct interpretation of the statement above. A. If random sampling is repeated, 95% of the confidence intervals created will capture the true mean. B. If random sampling is repeated, 95% of the samples will have a mean that is between 75 and 105 minutes. C. 95% of GRC students study between 75 and 105 minutes on average every day. D. There is 95% chance that the true mean is between 75 and 105 minutes.
1) Jaimie does a study on how many students have passed his classes in the past. He finds that 2739 have passed and 84 have failed. Construct a 95% confidence interval estimate of the proportion of students who pass.
Online News In a Harris poll of 2036 adults, 40% said that they prefer to get their news online. Construct a 95% confidence interval estimate of the percentage of all adults who say that they prefer to get their news online. Can we safely say that fewer than 50% of adults prefer to get their news online?
Subject: accounting

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