Skip has the following utility function: U(x, y) = x(y + 1), where x and y are quantities of two consumption goods whose prices are px and py respectively. Skip has a budget of B. Therefore the Skip’s maximization problem is x(y + 1) + λ(B − pxx − pyy) a) From the first order conditions find expressions for the demand functions x∗ = x(px, py, B) y∗ = y(px, py, B) Carefully graph x∗ and y∗. Graph Skip’s indifference curves. What kind of good is y? b) Verify that skip is at a maximum by checking the second order conditions. c) By substituting x∗ and y∗ into the utility function find an expressions for the indirect utility function, U = U(px, py, B)

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Chapter2: Second-order Linear Odes
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Skip has the following utility function: U(x, y) = x(y + 1), where x and y are quantities of
two consumption goods whose prices are px and py respectively. Skip has a budget of B.
Therefore the Skip’s maximization problem is
x(y + 1) + λ(B − pxx − pyy)
a) From the first order conditions find expressions for the demand functions
x∗ = x(px, py, B) y∗ = y(px, py, B)
Carefully graph x∗ and y∗. Graph Skip’s indifference curves. What kind of good
is y?
b) Verify that skip is at a maximum by checking the second order conditions.
c) By substituting x∗ and y∗ into the utility function find an expressions for the
indirect utility function,
U = U(px, py, B)
d) By rearranging the indirect utility function, derive an expression for the
expenditure function,
B∗ = B(px, py, U0)
Interpret this expression. Find ∂B/∂px and ∂B/∂py.
Skip’s maximization problem could be recast as the following minimization problem:
pxx + pyy s.t. U0 = x(y + 1)
e) Write down the lagrangian for this problem.
f) Find the values of x and y that solve this minimization problem and show
that the values of x and y are equal to the partial derivatives of the expenditure function, ∂B/∂px and ∂B/∂py respectively. (Hint: use the indirect utility
function)

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