Sketch the triangle. LA = 50°, ZB= 75°, c = 260 A 50° 50° 260 260 75° 75° B B O B B Solve the triangle using the Law of Sines. (Round side lengths to the nearest integer.) a = 260 75° 75° 260 50° 50° C A

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
SC
1
9
a
N
Sketch the triangle.
ZA = 50°,
O
O
2
A
W
A
S
ZB= 75°, C = 260
X
50°
#
50°
3
e
260
d
260
Solve the triangle using the Law of Sines. (Round side lengths to the nearest integer.)
a =
b =
ZC =
C
$
4
75°
C
75°
r
B
f
B
de i
%
5
V
O
t
B
B
וום
6
8.0
260
75°
y
b
75°
&
7
O
h
260
u
50°
510
00
8
0
n
C
A
9
Transcribed Image Text:SC 1 9 a N Sketch the triangle. ZA = 50°, O O 2 A W A S ZB= 75°, C = 260 X 50° # 50° 3 e 260 d 260 Solve the triangle using the Law of Sines. (Round side lengths to the nearest integer.) a = b = ZC = C $ 4 75° C 75° r B f B de i % 5 V O t B B וום 6 8.0 260 75° y b 75° & 7 O h 260 u 50° 510 00 8 0 n C A 9
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