Sketch the region that corresponds to the given inequalities. 2x + 4y 2 20 ys 5 x2 0, y 2 0 y y y 10 10 15 15 10 10 Solution Set Solution Set Solution Set + Isolution Set -10 -5 10 -15 -10 -5 10 15 -15 - 10 -5 10 15 -10 -5 10 -5 -5 -5 -5 -10 -10 10 -15 -15 10 Say whether the region is bounded or unbounded. O The region is bounded. O The region is unbounded. Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.) (х, у) - (х, у) - (x, y) =
Sketch the region that corresponds to the given inequalities. 2x + 4y 2 20 ys 5 x2 0, y 2 0 y y y 10 10 15 15 10 10 Solution Set Solution Set Solution Set + Isolution Set -10 -5 10 -15 -10 -5 10 15 -15 - 10 -5 10 15 -10 -5 10 -5 -5 -5 -5 -10 -10 10 -15 -15 10 Say whether the region is bounded or unbounded. O The region is bounded. O The region is unbounded. Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.) (х, у) - (х, у) - (x, y) =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Transcribed Image Text:Sketch the region that corresponds to the given inequalities.
2х + 4y 2 20
< 5
y < 5
x> 0, yΣ 0
y
y
y
y
10
15
15
10
10
10
Solution Set
Solution Set
Solution Set
ISolution Set
-10
10
-15
-10
-5
10
15
-15
-10
-5
10
15
-10
10
-5
-5
-5
-5
- 10
-10
10
15
-15|
10
Say whether the region is bounded or unbounded.
O The region is bounded.
O The region is unbounded.
Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.)
(х, у) %3D
(х, у) 3
(х, у) %3D
Expert Solution
Step 1
Since x5 and y5, so second and third graph cannot be the required region because in second one shaded region is above y=5 and in third one the shaded region is to the right of x=5.
Substitute 0 for x and y in the first inequality to decide the region.
In the obtained inequality is false, so the region is the one that do not contain the origin.
Hence , first graph is the correct option.
The region is bounded
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