PRACTICE ANOTHERSketch the region that corresponds to the given inequalities.14x +7y<707x + 14y< 707x +7y 42x 2 0, y 2 0yy10yy101010Solution SetSolution SetSolution SetSolution Set10-51010-510-10-510-10-510-5-5-5-51010-10-10Say whether the region is bounded or unbounded.O The region is bounded..O The region is unbounded.Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.)(x, y):(x, y) =(x, y) = (|(x, V) = ((x, y)%3DP Type here to search

Answered: aponds to the given inequalities 14 7ys…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Related questions

Question

PRACTICE ANOTHER
Sketch the region that corresponds to the given inequalities.
14x +
7y<70
7x + 14y< 70
7x +
7y 42
x 2 0, y 2 0
y
y
10
y
y
10
10
10
Solution Set
Solution Set
Solution Set
Solution Set
10
-5
10
10
-5
10
-10
-5
10
-10
-5
10
-5
-5
-5
-5
10
10
-10
-10
Say whether the region is bounded or unbounded.
O The region is bounded..
O The region is unbounded.
Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.)
(x, y):
(x, y) =
(x, y) = (|
(x, V) = (
(x, y)
%3D
P Type here to search

Expert Solution

Step 1

A mathematical statement, which states that two expressions are not equal is called an inequation and is denoted by $x \neq y$ .

A mathematical statement, which states that one expression is greater than the other in value is called an inequality.

The mathematical problems where we have to either maximize or minimize a linear function $z = a x + b y$ constrained by certain conditions in the form of linear inequalities are called Linear Programming problems.

Here a and b are constants and x and y are variables.

The linear function is called the objective function.

There are several methods to find the optimum solution for the objective function. Mostly we use the graphical method.

In the graphical method, we first find the critical points(corner points) and then substitute those points in the objective function to obtain the optimum solution.