Sketch the graph of a function with a jump discontinuity at x = 1. Then, evaluate the limits from the left, right, overall, and the value of the function you graphed at x = 1. Use proper notation.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Educational Website Content

#### Mathematical Analysis and Continuity

Welcome to our section on mathematical analysis and continuity. In this segment, we will explore concepts like jump discontinuities and the continuity of piecewise functions.

---

### Problem 4: Jump Discontinuity

**Task:**
Sketch the graph of a function that experiences a jump discontinuity at \( x = 1 \). After sketching, evaluate the limits from the left, the right, the overall limit, and the value of the function at \( x = 1 \), using proper mathematical notation.

**Steps:**
1. **Sketching the Graph:**
   - A jump discontinuity at \( x = 1 \) indicates that the function has different left-hand and right-hand limits at that point.
   - You'll draw two separate curves on either side of \( x = 1 \), ensuring they do not meet at \( x = 1 \).

2. **Evaluating the Limits:**
   - **Left-hand limit (\( \lim_{x \to 1^-} f(x) \))**: Determine the value the function approaches as \( x \) approaches 1 from the left.
   - **Right-hand limit (\( \lim_{x \to 1^+} f(x) \))**: Determine the value the function approaches as \( x \) approaches 1 from the right.
   - **Overall limit (\( \lim_{x \to 1} f(x) \))**: Since there is a jump discontinuity, the left-hand and right-hand limits will not be equal, thus the overall limit does not exist.
   - **Function value at \( x = 1 \) (\( f(1) \))**: Check the defined value of the function at \( x = 1 \).

---

### Problem 5: Continuity of a Piecewise Function

**Given Function:**
\[ 
h(x) =
\begin{cases} 
\frac{x^2 + 2x - 5}{x + 7} & \text{if } x \neq -3 \\
8 & \text{if } x = -3 
\end{cases}
\]

**Task:**
Discuss the continuity of the function \( h(x) \) at \( x = -3 \) and justify your answer using the concept of limits.

**Steps:**
1. **Function Analysis:**
Transcribed Image Text:### Educational Website Content #### Mathematical Analysis and Continuity Welcome to our section on mathematical analysis and continuity. In this segment, we will explore concepts like jump discontinuities and the continuity of piecewise functions. --- ### Problem 4: Jump Discontinuity **Task:** Sketch the graph of a function that experiences a jump discontinuity at \( x = 1 \). After sketching, evaluate the limits from the left, the right, the overall limit, and the value of the function at \( x = 1 \), using proper mathematical notation. **Steps:** 1. **Sketching the Graph:** - A jump discontinuity at \( x = 1 \) indicates that the function has different left-hand and right-hand limits at that point. - You'll draw two separate curves on either side of \( x = 1 \), ensuring they do not meet at \( x = 1 \). 2. **Evaluating the Limits:** - **Left-hand limit (\( \lim_{x \to 1^-} f(x) \))**: Determine the value the function approaches as \( x \) approaches 1 from the left. - **Right-hand limit (\( \lim_{x \to 1^+} f(x) \))**: Determine the value the function approaches as \( x \) approaches 1 from the right. - **Overall limit (\( \lim_{x \to 1} f(x) \))**: Since there is a jump discontinuity, the left-hand and right-hand limits will not be equal, thus the overall limit does not exist. - **Function value at \( x = 1 \) (\( f(1) \))**: Check the defined value of the function at \( x = 1 \). --- ### Problem 5: Continuity of a Piecewise Function **Given Function:** \[ h(x) = \begin{cases} \frac{x^2 + 2x - 5}{x + 7} & \text{if } x \neq -3 \\ 8 & \text{if } x = -3 \end{cases} \] **Task:** Discuss the continuity of the function \( h(x) \) at \( x = -3 \) and justify your answer using the concept of limits. **Steps:** 1. **Function Analysis:**
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