Sixty gym members were randomly selected and their weights were recorded and inputted intoMINITAB. The results are summarized in Exhibit 1 below.One-Sample Z: WeightTest of mu = 195 vs < 195The assumed standard deviation = 22.11VariableMeanStDevSE MeanWeight22.11*60193.13i.Calculate the value of *?ii.State the null and alternative hypotheses for the test.iii.What is the value of test statistic for this test.?iv.Calculate the p-value for this test.State the conclusion of this test. Give a reason for your answer.V.

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Description: Sixty gym members were randomly selected and their weights were recorded and inputted intoMINITAB. The results are summarized in Exhibit 1 below.One-Sample Z: WeightTest of mu = 195 vs < 195The assumed standard deviation = 22.11VariableMeanStDevSE M

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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Sixty gym members were randomly selected and their weights were recorded and inputted into
MINITAB. The results are summarized in Exhibit 1 below.
One-Sample Z: Weight
Test of mu = 195 vs < 195
The assumed standard deviation = 22.11
Variable
Mean
StDev
SE Mean
Weight
22.11
*
60
193.13
i.
Calculate the value of *?
ii.
State the null and alternative hypotheses for the test.
iii.
What is the value of test statistic for this test.?
iv.
Calculate the p-value for this test.
State the conclusion of this test. Give a reason for your answer.
V.

Expert Solution

Step 1

(i)

Obtain the value of standard error of mean.

The value of standard error of mean is obtained below as follows:

The value of standard error of mean is 2.8544.

Step 2

(ii)

State the hypotheses.

That is, the population mean equals 195.

That is, the population mean is less than 195.

(iii)

Obtain the value of the test statistic.

The value of the test statistic is obtained below:

Thus, the value of the test statistic is –0.66.

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