Six balls numbered 1 to 6 are placed in a bag. Some of the balls are grey and some are white. The balls numbered 2 and 5 are grey. The balls numbered 1, 3, 4, and 6 are white. A ball will be selected from the bag at random. The 6 possible outcomes are listed below. Note that each outcome has the same probability. Complete parts (a) through (c). Write the probabilities as fractions. (a) Check the outcomes for each event below. Then, enter the probability of the event. Outcomes Probabilit 1 3 6 Event A: The selected ball is white Event B: The selected ball has an even number on it Event A or B: The selected ball is white or has an even number on it Event A and B: The selected ball is white and has an even number on it (b) Compute the following. P(A) + P(B) - P(A and B) (c) Select the answer that makes the equation true. P(A) + P (B)-P(A and B)= P(A or B) 00 2 O O 0 S 4 5 0 3 3 3 3 0 0 3 > | دیا
Six balls numbered 1 to 6 are placed in a bag. Some of the balls are grey and some are white. The balls numbered 2 and 5 are grey. The balls numbered 1, 3, 4, and 6 are white. A ball will be selected from the bag at random. The 6 possible outcomes are listed below. Note that each outcome has the same probability. Complete parts (a) through (c). Write the probabilities as fractions. (a) Check the outcomes for each event below. Then, enter the probability of the event. Outcomes Probabilit 1 3 6 Event A: The selected ball is white Event B: The selected ball has an even number on it Event A or B: The selected ball is white or has an even number on it Event A and B: The selected ball is white and has an even number on it (b) Compute the following. P(A) + P(B) - P(A and B) (c) Select the answer that makes the equation true. P(A) + P (B)-P(A and B)= P(A or B) 00 2 O O 0 S 4 5 0 3 3 3 3 0 0 3 > | دیا
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:Six balls numbered 1 to 6 are placed in a bag.
Some of the balls are grey and some are white.
The balls numbered 2 and 5 are grey. The balls numbered 1, 3, 4, and 6 are white.
A ball will be selected from the bag at random.
The 6 possible outcomes are listed below.
Note that each outcome has the same probability.
2
6
Complete parts (a) through (c). Write the probabilities as fractions.
(a) Check the outcomes for each event below. Then, enter the probability of the event.
Outcomes
Probability
1
3
4 5 6
Event A: The selected ball is white
Event B: The selected ball has an even number on it
1
2
Event A or B: The selected ball is white or has an even
number on it
Event A and B: The selected ball is white and has an
even number on it
3
(b) Compute the following.
2
P(A) + P (B) – P(A and B)
=
3
(c) Select the answer that makes the equation true.
P(A) + P (B)- P(A and B)= P(A or B)
00
O
O
2
O
3
0
X
C.
>
0
>
0
0
3
3
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