sea has five nickels, three dimes, and seven pennies in his pocket. If he randomly Ks 2 coins without replacement, what is the probability of him choosing a nickel na penny? 1/6 1/7 7/45 1/15

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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### Question:

Hosea has five nickels, three dimes, and seven pennies in his pocket. If he randomly picks 2 coins without replacement, what is the probability of him choosing a nickel then a penny?

### Options:
- ⬜ 1/6
- ⬜ 1/7
- ⬜ 7/45
- ⬜ 1/15

### Explanation:

To find the probability of Hosea picking a nickel first and then a penny, we can follow these steps:

1. **Total Coins**: There are \(5 + 3 + 7 = 15\) coins in total.

2. **Probability of Picking a Nickel First**: 
   The probability of picking a nickel first is the ratio of the number of nickels to the total number of coins initially, which is \( \frac{5}{15} \).

3. **Probability of Picking a Penny Second**:
   After one nickel is picked, there are now 14 coins left. Since one of those picked isn't a penny, all 7 pennies would still be available.
   The probability of picking a penny is the ratio of the number of pennies to the remaining coins, which is \( \frac{7}{14} \).

4. **Combined Probability**:
   To find the combined probability of both events (selecting a nickel first and then a penny), multiply the two probabilities together:
   \[
   \frac{5}{15} \times \frac{7}{14} = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6}
   \]

**Therefore, the probability that Hosea picks a nickel and then a penny without replacement is \( \frac{1}{6} \). The correct answer is 1/6.**

### Final Answer:
- ✅ 1/6
- ⬜ 1/7
- ⬜ 7/45
- ⬜ 1/15
Transcribed Image Text:### Question: Hosea has five nickels, three dimes, and seven pennies in his pocket. If he randomly picks 2 coins without replacement, what is the probability of him choosing a nickel then a penny? ### Options: - ⬜ 1/6 - ⬜ 1/7 - ⬜ 7/45 - ⬜ 1/15 ### Explanation: To find the probability of Hosea picking a nickel first and then a penny, we can follow these steps: 1. **Total Coins**: There are \(5 + 3 + 7 = 15\) coins in total. 2. **Probability of Picking a Nickel First**: The probability of picking a nickel first is the ratio of the number of nickels to the total number of coins initially, which is \( \frac{5}{15} \). 3. **Probability of Picking a Penny Second**: After one nickel is picked, there are now 14 coins left. Since one of those picked isn't a penny, all 7 pennies would still be available. The probability of picking a penny is the ratio of the number of pennies to the remaining coins, which is \( \frac{7}{14} \). 4. **Combined Probability**: To find the combined probability of both events (selecting a nickel first and then a penny), multiply the two probabilities together: \[ \frac{5}{15} \times \frac{7}{14} = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6} \] **Therefore, the probability that Hosea picks a nickel and then a penny without replacement is \( \frac{1}{6} \). The correct answer is 1/6.** ### Final Answer: - ✅ 1/6 - ⬜ 1/7 - ⬜ 7/45 - ⬜ 1/15
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