Siven two particles with Q = 3.20-µC charges as shown in the figure below and a particle with charge q = 1.37 x 10-10 C at the origin. (Note: Assume a reference level of potential V = 0 at r= 0.) x= -0,800 m x= 0.800 m (a) What is the net force (in N) exerted by the two 3.20-uC charges on the charge q? (Enter the magnitude.) (b) What is the electric field (in N/C) at the origin due to the two 3.20-uC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 3.20-uC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 3.20-uc particles?
Siven two particles with Q = 3.20-µC charges as shown in the figure below and a particle with charge q = 1.37 x 10-10 C at the origin. (Note: Assume a reference level of potential V = 0 at r= 0.) x= -0,800 m x= 0.800 m (a) What is the net force (in N) exerted by the two 3.20-uC charges on the charge q? (Enter the magnitude.) (b) What is the electric field (in N/C) at the origin due to the two 3.20-uC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 3.20-uC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 3.20-uc particles?
College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Given two particles with Q = 3.20-µC charges as shown in the figure below and a particle with charge q = 1.37 x 1018 C at the origin. (Note: Assume a reference level of potential V = 0 at r = o.)
x = -0.800 m
x = 0.800 m
(a) What is the net force (in N) exerted by the two 3.20-uC charges on the charge q? (Enter the magnitude.)
(b) What is the electric field (in N/C) at the origin due to the two 3.20-µC particles? (Enter the magnitude.)
N/C
(c) What is the electrical potential (in kV) at the origin due to the two 3.20-µC particles?
kV
(d) What If? What would be the change in electric potential energy (in J) of the system if the charge
were moved a distance d = 0.400 m closer to either of the 3.20-µC particles?
Expert Solution
Step 1
"As per the guidelines i solved the first three subpart".
(a)
Since, the two charges are equal in magnitude and at equal distance from the origin, the magnitude of the force on charge due to both are equal.
The two charges are located on opposite sides of the test charge, the forces are in opposite direction.
Therefore, the resultant of the two equal and opposite forces on the charge will be equal to zero.
(b)
The electric field at the origin due to the two charges is,
Therefore, the resultant electric field at origin due to the two charges is zero.
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