siven the differential equation dy + 3t dt + 4y = 2 e" cos(5t) di2 Determine the Characteristic Equation for the given Differential Equation and then find its Solutions. A Characteristic Solutions: R, = 1 and R, = - 4 B Characteristic Solutions: R, = 1.24 and R, = -3.24
siven the differential equation dy + 3t dt + 4y = 2 e" cos(5t) di2 Determine the Characteristic Equation for the given Differential Equation and then find its Solutions. A Characteristic Solutions: R, = 1 and R, = - 4 B Characteristic Solutions: R, = 1.24 and R, = -3.24
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 17E: Find the general solution for each differential equation. Verify that each solution satisfies the...
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Question
q3
![Given the differential equation
d²y
dy
+ 3t
dt
+ 4y = 2 e cos(5t)
12
COS
|
di?
Determine the Characteristic Equation for the given Differential Equation and then find its Solutions.
(A Characteristic Solutions: R,
1 and R,
- 4
%3D
B)
Characteristic Solutions: R, = 1.24 and R,
1
= - 3.24
-3
C) Characteristic Solutions: R =
Characteristic Solutions: R = -1 ± i
E Characteristic Solutions: R,
-2 and R,
- 2
F)
Characteristic Solutions: R = - 1 ± 3 i
2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F182b42c4-24fc-41d2-99b8-0c7035c2fc63%2F803aae83-8796-4fe7-96f9-f778cea3b64c%2F20iq2zc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the differential equation
d²y
dy
+ 3t
dt
+ 4y = 2 e cos(5t)
12
COS
|
di?
Determine the Characteristic Equation for the given Differential Equation and then find its Solutions.
(A Characteristic Solutions: R,
1 and R,
- 4
%3D
B)
Characteristic Solutions: R, = 1.24 and R,
1
= - 3.24
-3
C) Characteristic Solutions: R =
Characteristic Solutions: R = -1 ± i
E Characteristic Solutions: R,
-2 and R,
- 2
F)
Characteristic Solutions: R = - 1 ± 3 i
2.
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