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Siven that System of knatted Cords 65 A 125 500dyn 1000 dyne To Determine that (9) What is the tension TA in CordA) (b) What is the tension TB in Cord B the tension T2 in (orde? (C) What is B

Siven that System of knatted Cords 65 A 125 500dyn 1000 dyne To Determine that (9) What is the tension TA in CordA) (b) What is the tension TB in Cord B the tension T2 in (orde? (C) What is B

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Given that Syltom of knatted 65 A 125 500dyn 1000 dyne To Determine that (9) What is the tension TA in CordA) the tension TB in Cord B2 (b) What is is the tension TΣ in lord 2 (C) What Now D65 3559 90-55=35° 155 Cords B 500dyn 115 80° 100⁰ 145. looodyn Now We Diagram TA = Con Consider Free Body Body Free Body For X 125 S TA = TA = 155 80 Soodyng 500 Smg Sm125 Now from equation 500 Ta Sm80= Smes 500 x Sm 80- Sm125 TA = TA = 500 0.9848 X 0-8191 492-4 08191 601-1476 dy ne 601-15 dy ne TB Sm155 Sm155 -Am from equation (1 She Smar 500 x Sm/155) Smils 500 x 0.4226 0-8151 211-3 0.8191 = 257- 97 dyne Diagram 145 Dius 10oodyne dow Tc = Smr 1000 x Smile" = TB = Free Body 100" Sm8= 0.3848 Sm 125= 0-8191 Sme 254 9660dyne For y Te APRying Solus Tes To= 1086-61 dyne 1000 (2) Smill5" 1000 x 0.9898 0-9063
Transcribed Image Text:Given that Syltom of knatted 65 A 125 500dyn 1000 dyne To Determine that (9) What is the tension TA in CordA) the tension TB in Cord B2 (b) What is is the tension TΣ in lord 2 (C) What Now D65 3559 90-55=35° 155 Cords B 500dyn 115 80° 100⁰ 145. looodyn Now We Diagram TA = Con Consider Free Body Body Free Body For X 125 S TA = TA = 155 80 Soodyng 500 Smg Sm125 Now from equation 500 Ta Sm80= Smes 500 x Sm 80- Sm125 TA = TA = 500 0.9848 X 0-8191 492-4 08191 601-1476 dy ne 601-15 dy ne TB Sm155 Sm155 -Am from equation (1 She Smar 500 x Sm/155) Smils 500 x 0.4226 0-8151 211-3 0.8191 = 257- 97 dyne Diagram 145 Dius 10oodyne dow Tc = Smr 1000 x Smile" = TB = Free Body 100" Sm8= 0.3848 Sm 125= 0-8191 Sme 254 9660dyne For y Te APRying Solus Tes To= 1086-61 dyne 1000 (2) Smill5" 1000 x 0.9898 0-9063
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