y* V. A stone is thrown upward from the top of a building, 45m high, at an angle a=30° to the horizontal and with an initial velocity Vo of magnitude 20 m/s. Take g-10m/s. Negled, friction. I) 45m a) What is the force acting on the stone along its path? Calculate its acceleration. b) Derive the parametric equations that describe the motion of the stone. c) Deduce the equation of the trajectory in terms of V, a, g and x. d) How long does it take the stone to reach the ground at point A? e) Determine the magnitude of the velocity vector as well as the angle B it makes with the horizontal just before it hits the ground. b) x 10/3t .y -5t + 10t + (tan a)x c) y = d) 4.16s e) v = 10v3, v, =-10t, + 10 = -31.6 so va = 36m/s B = 61.27° %3D
y* V. A stone is thrown upward from the top of a building, 45m high, at an angle a=30° to the horizontal and with an initial velocity Vo of magnitude 20 m/s. Take g-10m/s. Negled, friction. I) 45m a) What is the force acting on the stone along its path? Calculate its acceleration. b) Derive the parametric equations that describe the motion of the stone. c) Deduce the equation of the trajectory in terms of V, a, g and x. d) How long does it take the stone to reach the ground at point A? e) Determine the magnitude of the velocity vector as well as the angle B it makes with the horizontal just before it hits the ground. b) x 10/3t .y -5t + 10t + (tan a)x c) y = d) 4.16s e) v = 10v3, v, =-10t, + 10 = -31.6 so va = 36m/s B = 61.27° %3D
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I)
A stone is thrown upward from the top
of a building, 45m high, at an angle
a=30° to the horizontal and with an
initial velocity Vo of magnitude 20 m/s.
Take g=10m/s
Negled friction.
45m
a) What is the force acting on the stone
along its path? Calculate its
acceleration.
b) Derive the parametric equations that
describe the motion of the stone.
c) Deduce the equation of the trajectory in terms of Va, a, g and x.
d) How long does it take the stone to reach the ground at point A?
e) Determine the magnitude of the velocity vector as well as the angle B it makes
with the horizontal just before it hits the ground.
b) x = 10V3t ,y= -5t + 10t
c) y = +
2v cosa
+ (tan a )x
d) 4.16s
e) v, = 10V3, vy, = -10t, + 10 = -31.6 so v = 36m/s B = 61.27°
%3D
m
-- dA n fl T
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