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Situation: Water is pumped from one tank to another. Find: r/d=1, D₁ = 10 in, L₁= 50 ft. f2 = 0.020, 2₁ = 10 ft. D₂ = 10 in, L₂ = 950 ft, f2 = 0.020. 2₂ - 20 ft, T = 60°F. r/d = 1 L = 50 ft D = 10 in f= 0.020 T = 50°F Elevation 15 ft Elevation = 10 ft h, ft 80 60 40 20 O Discharge (ft³/s). Properties: From Table 10.5: Ke = 0.03; K = 0.35; KE = 1.0. Elevation = 20 ft L = 950 ft D = 10 in f= 0.020 Pump curve 1000 2000 3000 4000 5000 Q. gpm

Situation: Water is pumped from one tank to another. Find: r/d=1, D₁ = 10 in, L₁= 50 ft. f2 = 0.020, 2₁ = 10 ft. D₂ = 10 in, L₂ = 950 ft, f2 = 0.020. 2₂ - 20 ft, T = 60°F. r/d = 1 L = 50 ft D = 10 in f= 0.020 T = 50°F Elevation 15 ft Elevation = 10 ft h, ft 80 60 40 20 O Discharge (ft³/s). Properties: From Table 10.5: Ke = 0.03; K = 0.35; KE = 1.0. Elevation = 20 ft L = 950 ft D = 10 in f= 0.020 Pump curve 1000 2000 3000 4000 5000 Q. gpm

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Situation: Water is pumped from one tank to another. Find: r/d= 1, D₁ = 10 in, L₁ = 50 ft. f2 = 0.020, 21 = 10 ft. = D₂ 10 in, L2 = 950 ft, f2 = 0.020. Z₂ = 20 ft, T = 60°F. r/d = 1 L = 50 ft D = 10 in f = 0.020 T= 60°F Elevation 15 ft Elevation = 10 ft h, ft 80 60 40 20 0 Discharge (ft³/s). Properties: From Table 10.5: Ke = 0.03; K = 0.35; KE = 1.0. Elevation = 20 ft L = 950 ft D = 10 in f= 0.020 Pump curve 1000 2000 3000 4000 5000 Q, gpm
Transcribed Image Text:Situation: Water is pumped from one tank to another. Find: r/d= 1, D₁ = 10 in, L₁ = 50 ft. f2 = 0.020, 21 = 10 ft. = D₂ 10 in, L2 = 950 ft, f2 = 0.020. Z₂ = 20 ft, T = 60°F. r/d = 1 L = 50 ft D = 10 in f = 0.020 T= 60°F Elevation 15 ft Elevation = 10 ft h, ft 80 60 40 20 0 Discharge (ft³/s). Properties: From Table 10.5: Ke = 0.03; K = 0.35; KE = 1.0. Elevation = 20 ft L = 950 ft D = 10 in f= 0.020 Pump curve 1000 2000 3000 4000 5000 Q, gpm
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