SITUATION: Two people are debating electron flow versus conventional flow. One of them says that you will get different results predicting polarity of voltage drops in a resistive circuit depending on which convention you use. The other person says that the convention for labeling current does not matter at all, and the correct polarities will be predicted either way. QUESTION: Which of these two people is correct? Explain why, and give an example to prove your point.

SITUATION: Two people are debating electron flow versus conventional flow. One of them says that you will get different results predicting polarity of voltage drops in a resistive circuit depending on which convention you use. The other person says that the convention for labeling current does not matter at all, and the correct polarities will be predicted either way. QUESTION: Which of these two people is correct? Explain why, and give an example to prove your point.

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Pls help ASAP. Pls show all work and do all parts of the question.
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he voltage drop across the capacitor rises from 0 to ℰ. Note that ℰ is never actually known in the measurement. In fact, the oscilloscope voltage is decalibrated, so that, whatever ℰ is, ℰ is at the top line while zero is at the bottom line. We don't measure voltage levels, but rather 1/2, 1/4, and 1/8 the maximum. Kirchhoff's voltage law give: ℰ = IR + Q/C or the following: dQdt=−1RC(Q−EC)dQdt=−1RC(Q−ℰC) The solution for the capacitor voltage is VC(t)=E(1−e−t/RC)VC(t)=ℰ(1−e−t/RC) The voltage is zero at t = 0, t is the rising time, and you have to know when the rising begins. Now, calculate VC (in dev) when t = RC ln 2. R = 0.6 kΩ C = 2.3 μF
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