Situation: The context you find yourself in is that you have been given 24 meters of fencing material. You must maximize the rectangular area given this 24 meters of fencing. There are many rectangles that you can make using 24 meters of fencing, but only one that maximize the area for the children. Product, Performance, and Purpose: Start with the equation for perimeter of this rectangle 2L + 2W=24. done 2. Solve this equation for L, to get thtengih in terms of W. 3. Use this lengthin terms of W, to write an equation for the Area (remember, A=LW) in terms of W. This equation is your function, T(X)=your area equation. 4. Graph this function in your graphing calculator and use the table to find the x-value(width) that corresponds to the maximum y- value(which is area). This is the width that will maximize the area. Show your table. 5. To support your answer, use direct substitution to find the limit as x approaches this width of the function. This answer should match the y-value you found in the previous question. 6. Finally, state the dimensions, length and width, of the rectangle with perimeter 24 meters that gives the rectangle a MAXIMUM AREA.

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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answer the rest of the question that is not crossed out because they already answered the first part of it

Situation:
The context you find yourself in is that you have been given 24 meters of fencing material. You must maximize the rectangular area
given this 24 meters of fencing. There are many rectangles that you can make using 24 meters of fencing, but only one that maximizes
the area for the children.
Product, Performance, and Purpose:
done
Start with the equation for perimeter of this rectangle 2L + 2W=T.
2. Solve this equation for L, to get thetengih in terms of W.
3. Use this lengthrin terms of W, to write an equation for the Area (remember, A=LW) in terms of W. This equation is your function,
T(X)=your area equation.
4. Graph this function in your graphing calculator and use the table to find the x-value(width) that corresponds to the maximum y-
value(which is area). This is the width that will maximize the area. Show your table.
5. To support your answer, use direct substitution to find the limit as x approaches this width of the function. This answer should
match the y-value you found in the previous question.
6. Finally, state the dimensions, length and width, of the rectangle with perimeter 24 meters that gives the rectangle a MAXIMUM
AREA.
Transcribed Image Text:Situation: The context you find yourself in is that you have been given 24 meters of fencing material. You must maximize the rectangular area given this 24 meters of fencing. There are many rectangles that you can make using 24 meters of fencing, but only one that maximizes the area for the children. Product, Performance, and Purpose: done Start with the equation for perimeter of this rectangle 2L + 2W=T. 2. Solve this equation for L, to get thetengih in terms of W. 3. Use this lengthrin terms of W, to write an equation for the Area (remember, A=LW) in terms of W. This equation is your function, T(X)=your area equation. 4. Graph this function in your graphing calculator and use the table to find the x-value(width) that corresponds to the maximum y- value(which is area). This is the width that will maximize the area. Show your table. 5. To support your answer, use direct substitution to find the limit as x approaches this width of the function. This answer should match the y-value you found in the previous question. 6. Finally, state the dimensions, length and width, of the rectangle with perimeter 24 meters that gives the rectangle a MAXIMUM AREA.
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