SITUATION IV: A tension member is shown below and s subjected to a dead load of 15 kN and a live load of 20 kN. USE LRFD. The diameter of the bolts is 16 mm. Gross Area is 150 mm². Use Fy-250 MPa. Fu=375 MPa. 000 17. Compute for the safe load that could be carried by the tension member. a. 150 kN b. 500 kN
SITUATION IV: A tension member is shown below and s subjected to a dead load of 15 kN and a live load of 20 kN. USE LRFD. The diameter of the bolts is 16 mm. Gross Area is 150 mm². Use Fy-250 MPa. Fu=375 MPa. 000 17. Compute for the safe load that could be carried by the tension member. a. 150 kN b. 500 kN
Steel Design (Activate Learning with these NEW titles from Engineering!)
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Author:Segui, William T.
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Chapter3: Tension Members
Section: Chapter Questions
Problem 3.5.2P
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Answer 20-22
![SITUATION IV:
A tension member is shown below and
s subjected to a dead load of 15 kN and
a live load of 20 kN. USE LRFD. The
diameter of the bolts is 16 mm. Gross
Area is 150 mm?. Use Fy=250 MPa,
Fu=375 MPa.
1
000
17. Compute for the safe load that
could be carried by the tension
member.
a. 150 kN
b. 500 kN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24136d6a-2ea0-450e-a810-06280feceea1%2F6207e37b-4447-4405-8896-986a2d53a58f%2Fhzlsfg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:SITUATION IV:
A tension member is shown below and
s subjected to a dead load of 15 kN and
a live load of 20 kN. USE LRFD. The
diameter of the bolts is 16 mm. Gross
Area is 150 mm?. Use Fy=250 MPa,
Fu=375 MPa.
1
000
17. Compute for the safe load that
could be carried by the tension
member.
a. 150 kN
b. 500 kN
![c. 350 kN
d. 550 kN
18. Solve for the design loadP
based on yielding of gross section.
a. 506.25 kN
c. 350.45 kN
b. 500 kN
d. 316.62 kN
19. Solve for the design load P
based on ruplure of the net area.
Use additional 2mm for diameter of
hole and thickness of plate is 5 mm.
a. 506.25 kN
b. 500 kN
c. 350.45 kN
d. 316.62 kN
20. What is the design strength for
LRFD?
a. 506.25 kN
b. 421.88 kN
C. 350.45 kN
d. 316.62 kN
21. What is the design strength for
ASD for the rupture of the net area?
a. 506.25 kN
b. 500 kN
c. 350.45 kN
d. 264.375 kN
22. Compute for the block shear
strength if the plate, see the cut
section 1 for reference.
a. 481.50 kN
c. 372.50 kN
b. 532.50 kN
d. 264.38 kN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24136d6a-2ea0-450e-a810-06280feceea1%2F6207e37b-4447-4405-8896-986a2d53a58f%2F0zyyigp7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:c. 350 kN
d. 550 kN
18. Solve for the design loadP
based on yielding of gross section.
a. 506.25 kN
c. 350.45 kN
b. 500 kN
d. 316.62 kN
19. Solve for the design load P
based on ruplure of the net area.
Use additional 2mm for diameter of
hole and thickness of plate is 5 mm.
a. 506.25 kN
b. 500 kN
c. 350.45 kN
d. 316.62 kN
20. What is the design strength for
LRFD?
a. 506.25 kN
b. 421.88 kN
C. 350.45 kN
d. 316.62 kN
21. What is the design strength for
ASD for the rupture of the net area?
a. 506.25 kN
b. 500 kN
c. 350.45 kN
d. 264.375 kN
22. Compute for the block shear
strength if the plate, see the cut
section 1 for reference.
a. 481.50 kN
c. 372.50 kN
b. 532.50 kN
d. 264.38 kN
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