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SITUATION III: A beam has a width of 250 mm and has an effective depth of 350 mm. It is cantilevered at a span of 5m and has a uniformly distributed dead load of 25 * including its own weight. 10mm- diameter bars are used as stirrups for the beam with /y = 275 MPa. Use fc = 24 MPa.

SITUATION III: A beam has a width of 250 mm and has an effective depth of 350 mm. It is cantilevered at a span of 5m and has a uniformly distributed dead load of 25 * including its own weight. 10mm- diameter bars are used as stirrups for the beam with /y = 275 MPa. Use fc = 24 MPa.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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SITUATION III: A beam has a width of 250 mm and has an effective depth of 350 mm. It is cantilevered at a span of 5m and has a uniformly distributed dead load of 25 including its own weight. 10mm- diameter bars are used as stirrups for the beam with fy 275 MPa. Use fc = 24 MPa.
Transcribed Image Text:SITUATION III: A beam has a width of 250 mm and has an effective depth of 350 mm. It is cantilevered at a span of 5m and has a uniformly distributed dead load of 25 including its own weight. 10mm- diameter bars are used as stirrups for the beam with fy 275 MPa. Use fc = 24 MPa.
15. Compute for the shear capacity of vertical stirrups. b. 46.41 kN d. 88.80 kN а. 42.39 kN C. 74.00 kN for the theoretical 16. Compute spacing needed for critical shear. а. 300 mm b. 206.74 mm c. 150 mm d. 600 mm 17. Compute for the maximum spacing needed for critical shear. b. 206.74 mm d. 600 mm a. 300 mm С. 150 mm
Transcribed Image Text:15. Compute for the shear capacity of vertical stirrups. b. 46.41 kN d. 88.80 kN а. 42.39 kN C. 74.00 kN for the theoretical 16. Compute spacing needed for critical shear. а. 300 mm b. 206.74 mm c. 150 mm d. 600 mm 17. Compute for the maximum spacing needed for critical shear. b. 206.74 mm d. 600 mm a. 300 mm С. 150 mm
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