SITUATION II: For a single C15 x 33.9 fastened to a ½ inches gusset plate. Use A36 steel (Fy = 36 ksi & Fu = 58 ksi) and assume holes for 4 inch diameter bolts. U = 0.869 a. Determine the maximum tensile load using LRFD. b. Determine the maximum tensile load using ASD.

SITUATION II: For a single C15 x 33.9 fastened to a ½ inches gusset plate. Use A36 steel (Fy = 36 ksi & Fu = 58 ksi) and assume holes for 4 inch diameter bolts. U = 0.869 a. Determine the maximum tensile load using LRFD. b. Determine the maximum tensile load using ASD.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Connections

In steel structures, connections are the members that join two or more steel members. The connections are the most important members of any steel structure, and hence, they are designed more carefully. The majority of the construction cost of steel structures is incurred due to the connections. The design of connections is done as per the recommendations and specifications of the American Institute of Steel Construction (AISC).

Question

SITUATION II:
For a single C15 x 33.9 fastened to a ½ inches gusset plate. Use A36 steel (Fy = 36 ksi &
Fu = 58 ksi) and assume holes for %4 inch diameter bolts. U = 0.869
a. Determine the maximum tensile load using LRFD.
b. Determine the maximum tensile load using ASD.

3in.
3in.
3in.
1/2 in. Gusset Plate
3in. 3in.
1.5in.
1.5in.
Properties of C15x33.9:
A = 10.0 in.²
d = 15.0 in.
b = 3.40 in.
t = 0.650 in.
tw = 0.400 in.
* = 0.788 in.

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Step 1: Introducing Given Data

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Step 2: Calculation of net area (An)

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Step 3: Calculation of net effective area (Ae)

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Step 4: Calculation of Nominal strength in yielding & rupture

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Step 5: Calculation of design strength using LRFD

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Step 6: Calculation of Allowable strength using ASD

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