SITUATION 4 Consider the following two probability distributions: 5!(0.99)" (0.01) -ª æ!(5-x)! 5-x 9 (x) = х 3 0, 1, 2, 3, 4, 5 20000 f (x) = (x+100) x > 0 (a) Considering f(x), determine P(x >= 2.0) and P(0.5 < x < 1.5). (b) Considering g(x), determine P(x = 2), P(1 < x < 4) and P(x >=

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Chapter1: Combinatorial Analysis
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Question 4

SITUATION 4
Consider the following two probability distributions:
g (x) =
5!(0.99)" (0.01)5-ª
æ!(5-x)!
х 3 0, 1, 2, 3, 4, 5
20000
f (x) =
x > 0
(x+100)
(a) Considering f(x), determine P(x >=
2.0) and P(0.5 < x < 1.5).
(b) Considering g(x), determine P(x = 2), P(1 < x < 4) and P(x >= 5)
Transcribed Image Text:SITUATION 4 Consider the following two probability distributions: g (x) = 5!(0.99)" (0.01)5-ª æ!(5-x)! х 3 0, 1, 2, 3, 4, 5 20000 f (x) = x > 0 (x+100) (a) Considering f(x), determine P(x >= 2.0) and P(0.5 < x < 1.5). (b) Considering g(x), determine P(x = 2), P(1 < x < 4) and P(x >= 5)
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