SITUATION 2:In its natural state, a moist soil has avolume of 0.33 ft³ and weighs 39.93 lb.The oven- dried weight of the soil is34.54 lb. If G= 2.67,5. Calculate the moisture content.b. 15.6%d. 14.1%a. 16.7%c. 17.9%6. Calculate the moist unit weight.a. 112 Ib/ftc. 168 Ib/ft?b. 143 Ib/ftd. 121 Ib/ft

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Answered: SITUATION 2: In its natural state, a…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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01. The wet weight of 29.9 x 10 -4 m3 of soil is 62.7 N. If the moisture content is 11.6% and the specific gravity of the solids is 2.67, determine the following: IT IS REQUESTED: A) Wet unit weight (KN/m3; lb/ft3) D) Saturated unit weight (KN/m3; lb/ft3) B) Dry unit weight (KN/m3; lb/ft3). E) degree of saturation. C) Void ratio F) Volume occupied by water (m3)
8- If air content and degree of saturation are represented as a, and S respectivery, then the relationship between them is A) a, = 9- In wet soil mass, air occupies one-seventh of its volume and water occupies one- eighth of its volume the void ratio of soil is A) 0.25 The relationship between ysat , Ggand e is B) a, = 1-S C)S = 1+a. D) S = a. B) 0.36 C) 0.43 D) I 10- A) Ysat = 1+e (G e)Yw B) Ysat = 1te (G,+e)Yw C) Ysat = 1+e (G;te) D) Ysat %3D 1le 1- The relationship between y sat Ya: Y and S is A) y = Ya SlYsat - Yal B) y = Yd STYsat-Yal C) y = Ya + S[Ysat - Yal D) y = Ya - S[Ysat - Yal
2 The moist unit weight of a soil at 18.32% moisture is 17.23 kN/m3. Determine the mass of water (kg), per cubic meter, that must be added to reach full saturation. The specific gravity of soil solids is 2.63. Round off to two decimal places.
Soil Mechanics (1) For a soil, the following are given: Specific gravity = 2.67, moist unit weight = 17.6 kN/m³, water unit weight = 9.81 kN/m3 and moisture content = 12 %. Determine (a) Dry unit weight, (b) Void ratio, (c) Porosity, (d) Degree of saturation
In natural state, a moist soil has a volume of 0.33 ft3 and weighs 39.93 lb. The oven dry weight of the soil is 34.54 lb. If Gs= 2.71, calculate the degree of saturation.
Soil
An undisturbed specimen of soil has a volume of 300 cm3 and weighs 498 g. After over drying for 24 hours, its weight is reduced to 456 g. Assume G= 2.70 . Determine the water content in percent. a.21.9 b.9.21 c.43.8 d.78
In natural state, a moist soil has a volume of 0.33 ft3 and weighs 39.93 lb. The oven dry weight of the soil is 34.54 lb. If Gs= 2.71, calculate the volume of the water in ft3.
in its natural state. A moist soil has a volume of 9.34x10-3 m3 and weighs 180x10-3kN. The oven-dried weight of the soil is 150x10-3kN. If Gs=2.67, calculate 1) moisture content(%) 2) moist unit weight (kN/m3)
For soil in natural state, given e - 0.8, w=24%, and Gs = 2.68. (a) Determine the bulk unit weight, dry unit weight, and degree of saturation. (b) If the soil is made completely saturated by adding water, what would its moisture content be at that time? Also find the saturated unit weight.
If the soil has a capacity to hold water at 35%, with hygroscopic water of 5%, and you added 40%, how much is the unavailable water? *a.) 10%b.) 30%c.) 5%d.) 0
Z

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