2. A 0.450 m³ moist soil sample has the following: Moist mass = 721.2 kg ; Dry mass = 633.9 kg ; Specific gravity of soil solids = 2.68 Determine: а. Moisture content.W % b. Moist density P=, kg/m³ Dry density, Pa = kg/m³ с. d. Void ratio, e= Porosity. n= е.
2. A 0.450 m³ moist soil sample has the following: Moist mass = 721.2 kg ; Dry mass = 633.9 kg ; Specific gravity of soil solids = 2.68 Determine: а. Moisture content.W % b. Moist density P=, kg/m³ Dry density, Pa = kg/m³ с. d. Void ratio, e= Porosity. n= е.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![2.
A 0.450 m³ moist soil sample has the following: Moist mass = 721.2 kg ; Dry mass = 633.9 kg ;
Specific gravity of soil solids = 2.68 Determine:
а.
Moisture content.W =
b.
Moist density P=,
kg/m³
Dry density, Pa =.
kg/m³
с.
d.
Void ratio, e=
Porosity. n=
е.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05ed325b-91f6-4542-8592-ed58430cf2a2%2F28fba925-6d9c-46a5-9e57-6a5ee552013d%2Fxdezq3k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2.
A 0.450 m³ moist soil sample has the following: Moist mass = 721.2 kg ; Dry mass = 633.9 kg ;
Specific gravity of soil solids = 2.68 Determine:
а.
Moisture content.W =
b.
Moist density P=,
kg/m³
Dry density, Pa =.
kg/m³
с.
d.
Void ratio, e=
Porosity. n=
е.
Expert Solution
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Step 1
Mass of moist soil(Mmoist)=721.2 Kg
The volume of sample(V)=0.450 m3
Mass of dry soil(Mdry)=721.2 Kg
Specific gravity(G)=2.68
a) water content(w)=
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