Situation 14: A sample of dry coarse-grained material was shaken through a nest of sievesand following results were obtained:Diameter (mm)4.7502.000Sieve No.Mass Retained (grams)41014.80200.85098.00400.42590.101000.150181.902000.075108.80Pan6.1042. Which of the following most nearly gives the effective diameter of the soil sample?c. 0.12mmd. 0.06mma. 0.10mmb. 0.08mm43. Which of the following most nearly gives the uniformity coefficient of the soil sample?(D6o = 0.44mm)а. 6.93b. 6.48с. 4.40d. 5.2144. Which of the following most nearly gives the coefficient of curvature of the soil sample?(D30 = 0.19mm)а. 0.61b. 0.82с. 0.53d. 1.10USDA Texturel Cle eniiegtion Suvotem

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Answered: Situation 14: A sample of dry…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 89 20 0.850 71 40 0.425 47 60 0.250 21 100 0.150 14 200 0.075 7 Pan --- 0 Determine the value of the coefficient of uniformity. Round off to three decimal places.
Problem A: For questions 1 to 7. In the given results of the sieve analysis of a soil. Calculate the following; U.S. Opening Mass Sieve (mm) Retained, grams 4 4.75 10 2.00 21.6 20 0.850 49.50 40 0.425 102.60 60 0.250 89.10 100 0.150 95.60 200 0.075 60.4 Pan 31.2 Sum 1) For the problem above the most probable value for D10=. a) 0.15 mm 2) For D30 =_ a) 0.17 mm 3) For Dso = ? a) 0.27 mm 4) The Uniformity coefficient will be ? a) 4.56 5) The Coefficient of Gradation is? a) 0.90 6) The particle size distribution curve is what type? a) Gap-graded 7) Using the AASHTO system what is the percentage of sand? a) 6.90 b) 0.25 mm c) 0.67 mm d) 0.09 mm b) 0.27 mm c) 0.185 mm d) 0.03 mm b) 0.41mm c) 1.05 mm d) 0.21 mm b) 4.78 c) 3.98 d) 4.21 b) 0.93 c) 0.96 d) 1.15 b) Poorly Graded c) Well-graded b) 4.88 c) 72.90 d) 88.30
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 88 20 0.850 70 40 0.425 50 60 0.250 21 100 0.150 13 200 0.075 5 Pan --- 0 Determine the value of the coefficient of uniformity. Round off to three decimal places.
Situation 3. Following are the results of a sieve analysis. Determine: a. Cu b. Cc c. So Sieve No. 4 6 10 20 40 60 100 200 Pan Diameter (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Soil Sample Mass Retained (g) 100 180 86 160 105 134 110 65 45
Attempt 10 The weight percent of silicon in six different rock samples, each containing different amounts of silicon, was measured different methods. The results are given in the table. two Sample Method A Si wt% Method B Si wt% 1 11.570 11.550 2 15.380 15.290 3 17.950 17.830 4 22.840 22.810 5 25.110 25.170 6 27.070 27.030 Determine feale- 0.300 feale Incorrect Determine fuable at the 95% confidence level. A list of r values can be found in the Student's r table.
Problem 1: A sieve analysis of 1,135 grams of fine rock yields the following data in the table. The size of a sieve Restrained in each a Through a sieve(gr) sieve (gr) % in 1135 ½ in 56 1079 % in. 171 908 NO.4 262 646 NO.8 203 443 NO.30 182 261 NO.50 68 193 NO.100 57 136 NO.200 51 85 Pan 85 The total weight of example 1135 grams
Soil
Given below is the result of a sieve analysis done on a soil sample.Sieve No. Diameter Percent Passing %4 4.750 9510 2.000 8220 0.850 7340 0.425 5360 0.250 23100 0.150 14200 0.075 7Pan --- 0Determine the value of the coefficient of uniformity
Problem 4: The following are the results of a sieve analysis. a. Determine the percent finer than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, D60, for the soil. c. Calculate the uniformity coefficient Cu. d. Calculate the coefficient of gradation Cc. U.S. Sieve N 4 10 20 40 60 100 200 Pan U.S. Sieve N Mass of Soil Retained (g) Problem 5: Repeat problem 4 with the following data. 4 6 10 20 40 60 100 200 Pan 0 18.5 53.2 90.5 81.8 92.2 58.5 26.5 Mass of Soil Retained (g) 0 0 0 9.1 249.4 179.8 22.7 15.5 23.5
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 95 10 2.000 83 20 0.850 69 40 0.425 50 60 0.250 27 100 0.150 13 200 0.075 7 Pan --- 0 Determine the value of the coefficient of uniformity. ROUND OFF TO THREE DECIMAL PLACES. USE STORED VALUES.
Calculate K for the soil tested in the figure. Assume the cross-sectional area of the sample is 14 cm² and the area of the standpipe is 2cm². The time of test = 15 min. All dimensions shown are in mm. D 270 T 200 soil 70 580 310

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