SITUATION 1. A simple curve has a central angle of 36° and a degree of curve of 6º. Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the point of curvature and point of tangency. 8.934m 4.893m 3.489m 9.348m

Q: The azimuth from south of the tangent from PC to Pl is 223 degrees and PI to PT is 323 degrees. The…

A: Given data, PC=223°-azimuth PI-PT=323° Central angle=41° Distance,V1-V2=490.1 m…

Q: 6. A compound curve has a central angle of the first curve equal to 40° and a radius of 280m. while…

A: R1 = 280m D2 = 5NOTE : As per guidelines, first question is solved. Request you to post remaining…

Q: A compound curve connects three tangents having an azimuths of 250°, 270 ° and 290° respectively.…

A: The given data is: The azimuths are 250°, 270 °, and 290° The length of the chord=340m

Q: The tangent at the beginning of the curve at the P.C. is 125.70 m long and that at the P.T. is 155.6…

A:

Q: Two straight lines intersect at an angle of 60°. The radius of a curve joining the two straight…

A: Angle of intersection θ=60o Radius of curve R=600 m,   It is needed to find the length of long chord…

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