Situation 1A sample of soil has the following grain-sizecharacteristics:* SOIL CLAsIRCATION100• TRIANGULAR CIASFICATION CHART (by vsDA)VEDA- US Departntent of AgriculiturePercent PassingSize (mm)2.0000.0750.051010090-7420ProceduneO ldentéy % of solcomponents% grovel-*% sand = %Pasangacoomm- % Passingo omam% salt60800.005323070100% - % Passtnga.coomm0.00215.Clay40Determine the following:1. Percentage of silt2. Classification of the soil using the Triangular60-- %Pasingo.esonn - %Pasungoonamm- O%.30Siltyclay2 Plot the %sand, % slt, and Xclay on therrepective aes on the trianguar chart loyprojectng ines pependicular to the oves.The point of eterection of those Ines s takenCb the appropriate sol carfication.Classification Chart.Sảndyclay6040/Silty claykamClay loàmSoil7030Sandy clayloam8020-Silty koam90Notes:10LianySandsindSandy loamsol componentparticde aze (mm)100gravelsond>2.00omm10090706050403020102000 Mm- O.ocommOOomm- O.coammPercentage of sandsiltalay<0.002 mmPercentage of siltPeromtage of elay

Answered: Image /qna-images/answer/feb01700-ecde-42bb-a29e-44c6d3a42c7b.jpg

Situation 1 A sample of soil has the following grain-size * SCIL CLASSIRCAION characteristics: Size (mm) 2.000 0.075 0.05 0.005 100 • TRIANGULAR CLASICATON CHART (by USDA) VSDA- US Departmtart of Agriculture Percent Passing 10 100 90 74 20 Proene 60 O ldentéy % of solcomponents % grovel- 100% - % Pannga conmm *% sond - % Pasaangacomm- %Passingoomnn "% salt- Paaingoesonn - %Pasungsamm *% clog- %Posngoanm - 0%. 32 70 0.002 15 Cly 40 Determine the following: 1. Percentage of silt 2. Classification of the soil using the Triangular Classification Chart. 60 Silty O Plet the % sand, % sit, and %cloy on ther repective es on the trianguar chart loy projectng ines peperdtcular to the oes O The point of nerction of thove ines taken Ch the apropriate sol dorficotion. Sind clay 60 Silty clay loa Clay loam Soil 70 Sandy clay kaim 80 20 Loàm Silty kiam 90 Notes: 10 Sandy kam sol corponent porticie ste (mm) Sand ind Sill 100 gravel sand sit >200omm 100 90 70 60 50 40 30 20 10 2000 Mm- O.Osomm OOomm - O.coomm Percentage of sand cloy <0.00a mm Percentage of si Petutage of clay

Situation 1 A sample of soil has the following grain-size * SCIL CLASSIRCAION characteristics: Size (mm) 2.000 0.075 0.05 0.005 100 • TRIANGULAR CLASICATON CHART (by USDA) VSDA- US Departmtart of Agriculture Percent Passing 10 100 90 74 20 Proene 60 O ldentéy % of solcomponents % grovel- 100% - % Pannga conmm % sond - % Pasaangacomm- %Passingoomnn "% salt- Paaingoesonn - %Pasungsamm % clog- %Posngoanm - 0%. 32 70 0.002 15 Cly 40 Determine the following: 1. Percentage of silt 2. Classification of the soil using the Triangular Classification Chart. 60 Silty O Plet the % sand, % sit, and %cloy on ther repective es on the trianguar chart loy projectng ines peperdtcular to the oes O The point of nerction of thove ines taken Ch the apropriate sol dorficotion. Sind clay 60 Silty clay loa Clay loam Soil 70 Sandy clay kaim 80 20 Loàm Silty kiam 90 Notes: 10 Sandy kam sol corponent porticie ste (mm) Sand ind Sill 100 gravel sand sit >200omm 100 90 70 60 50 40 30 20 10 2000 Mm- O.Osomm OOomm - O.coomm Percentage of sand cloy <0.00a mm Percentage of si Petutage of clay

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 96 6 2.380 91 10 2.000 89 20 0.840 85 40 0.420 81 60 0.250 78 100 0.149 67 200 0.074 64 LL 40 PL 30 Determine its classification using USCS. ML MH None of the above CL CH
Classify the following soils by the Unified soil classification system. Give the group na soil Soil 1 2 Sieve analysis (percentage finer) Liquid Plastic No. 4 No. 200 limit limit 98 28.5 33.2 22.6 95 10 30 22 D10 D30 8 D60 0.085 0.12 0.135 Q1)
The Name :- Answer the following questions :-( Choose 5 only) 1- .is the moisture content that defines where the soil changes from a plastic to a viscous fluid state. 2- The difference between the PL and the LL is defined as.... 3- Why is it not possible to use core cutter method for calculating the density of cohesion less soil? 4- The relative density of a soil is 5- In the sieve analysis test Place the sieve stack in the mechanical shaker and shake for . minutes . 6- Hydrometer testing is performed on soil passing from a sieve.
SITUATION 2: From the following data of a given sieve analysis: Sieve No. # 4 Opening Percent (mm) 4.76 2.38 2.0 0.71 0.25 0.149 0.074 passing 90 #8 #10 #25 # 60 #100 # 200 64 58 30 22 10 4 9. Determine size(D10). а. 0.20 с. 2.0 10. Determine Cu. а. 10 C. 20 the effective grain b. 0.15 d. 0.09 b. 15 d. 5
Classify the following soil by the Unified Soil Classification System. Percent passing No. 4 sieve = 82Percent passing No. 10 sieve = 71Percent passing No. 40 sieve = 64Percent passing No. 200 sieve = 41Liquid limit = 31Plasticity index = 12
A sample o f soi l compacte d accordin g t o a standar d Proctor test ha s a unit weight of 130.9 lb/ft 3 at 100 % compaction and at optimum water content o f 14% . What is the dryunit weight? If the voids become fille d with water what would be the saturated unit weight?Assume Gs = 2.67.
The result of the particle-size analysis of a soil are as follows: Sieve No. % Passing 10 40 200 100 80 58 7. The liquid limit and plasticity index of the soil are 30 and 10, respectively. Classify the soil by AASHTO Classification system. а. А-4 (3) b. A-4(4) A-5(3) d. A-5(4) C.
From the particle size distribution curve, about 61% of the oil is finer than 0.074 mm in diameter. The liquid limit and plastic limit of minus No 40 fraction of the soils are as follows: LL =26, PL= 20. Classify the soil using the USCS.a. CL-MLb. CL-MLc. SP-SCd. CH
1. Classify the following soils using USCS and give the group symbols. Sieve Analysis, % finer Soil Liquid Limit No. 4 No. 200 1 (SC) 70 30 33 2 (GC) 48 20 41 3 (CH) 95 70 52 4 (CL) 100 82 30 5 (CL) 100 74 35 6 (SC) 87 26 38 7 (CH) 88 78 69 8 (CH) 99 57 54 9 (SP-SC) 71 11 32 10 (SW) 100 2 11 (CL) 89 65 44 12 (SP-SC) 90 8 39 Plasticity Index 21 22 28 19 21 18 38 26 16 NP 21 31 Cu 4.8 7.2 3.9 Cc 2.9 2.2 2.1
Question 2 For shown particle size distributions, find coefficient of uniformity (Cu) and the coefficien curvature (C. )for each soil; BS sieves 63 pm 212am 600um 2mm 6,3mm 20mm 62mm 100 90 so 10 Gravel Fire MedumCoare Fine MedymConrse Fne Medium CoareCoobles 0.01 Clay 10 10 0.001 Particle size (mm) Percentage smallr
Question 12 Classify the following soils using the Unified soil classification system. Give the group symbol. No. 4 = 100 No. 200 = 45 LL = 36 PL = 22 A) SC B SP SM GC
• Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure % Finer Clay 100 90 80 70 60 50 40 30 20 10 0 0.001 + Silt Soil A Sand Soil B 0.01 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A B 1. Classify these soils according to USCS and ASTM-CS 2. Is either of the soils organic? LL 26 (oven-dried; assume same for not dried) Nonplastic PL 18