Single Stage Vapor Compression (SSVC) refrigeration system has a cooling capacity of 7.5 tons. The following are the actual conditions: discharge of the evaporator is at -30°C & 0.2 MPa, discharge of the condenser is at 30°C & 2.0 MPa, discharge of the compressor is at 130°C & 2.5 MPa. Determine the COP of the system.
Single Stage Vapor Compression (SSVC) refrigeration system has a cooling capacity of 7.5 tons. The following are the actual conditions: discharge of the evaporator is at -30°C & 0.2 MPa, discharge of the condenser is at 30°C & 2.0 MPa, discharge of the compressor is at 130°C & 2.5 MPa. Determine the COP of the system.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
A Single Stage Vapor Compression (SSVC) refrigeration system has a cooling capacity of 7.5 tons. The following are the actual conditions: discharge of the evaporator is at -30°C & 0.2 MPa, discharge of the condenser is at 30°C & 2.0 MPa, discharge of the compressor is at 130°C & 2.5 MPa. Determine the COP of the system.
![PRESSURE, MPa
20
10
8
6
4
2
1
0.8
0.6
0.4
0.2
0.1
0.08.
0.06
0.04
0.02
0.01
0
0
R-32
(difluoromethane)
100
Reference state:
h = 200.0 kJ/kg, s= 1.00 kJ/(kg-K)
for saturated liquid at 0°C
1300:
-0.40
+0.50
1250:
-80
-70;
-60
-50°C
-40
-30
-20
I
100
0.60
-0.70
1200
Properties computed with: NIST REFPROP
version 7.0
Saturated Liquid
1150-
+0.1
200
0.2
1100:
-10-
0
10
0.80
-0.90
1.00
1.10
200
1050-
0.3-
1000
1.20
1.30
X = 0.4
88/9 8 849
1.40
300
1.50
006
0.5%
1.60-0
-80
-60
300
SOL
-50
T=-30°C
-40
0.6
-008
-1.80
-10
1.90
0
10
0.7
400
2.00-
700,
20
30
40
-2.10
600
400
20
50
ㅎ 888 엉...
0.8
500-
W
0.9
2.20-1
2.30
-2.40
ENTHALPY, KJ/kg
2.50
500
400
Saturated Vapor
500
-20:
300
20
2.80
+A--
77
X
40
600
60
2.90
A
K
H
The
A
ai
i
TR
600
AN
15
+-+-₂
7.
80
100
4
3.00
S
p = 200 kg/m³
150
V
1
120-
+140
----
A
M
= 3.10 kJ/(kg.
160
·K)₂
S
700
100-
1
T
3.20
08
X
60
T = 180°C
3.30
700
1.
40
30
20
15
002.
10
8.0
6.0
4.0
3.0
2.0
1.5
1.0
0.80
0.60
0.40
0.30
0.20
800
20.
10.
8
6
2
1
0.8
0.6
0.4
0.2
0.1
0.08
0.06
0.04
0.02
0.01
800
Based on formulation of Tillner-Roth and Yokozeki (1997)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F03237d7f-fdce-47b8-a8a2-758f3f9c36f5%2Fc469fe1c-4053-4b47-91f7-24add1db92c5%2F1id4m2e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:PRESSURE, MPa
20
10
8
6
4
2
1
0.8
0.6
0.4
0.2
0.1
0.08.
0.06
0.04
0.02
0.01
0
0
R-32
(difluoromethane)
100
Reference state:
h = 200.0 kJ/kg, s= 1.00 kJ/(kg-K)
for saturated liquid at 0°C
1300:
-0.40
+0.50
1250:
-80
-70;
-60
-50°C
-40
-30
-20
I
100
0.60
-0.70
1200
Properties computed with: NIST REFPROP
version 7.0
Saturated Liquid
1150-
+0.1
200
0.2
1100:
-10-
0
10
0.80
-0.90
1.00
1.10
200
1050-
0.3-
1000
1.20
1.30
X = 0.4
88/9 8 849
1.40
300
1.50
006
0.5%
1.60-0
-80
-60
300
SOL
-50
T=-30°C
-40
0.6
-008
-1.80
-10
1.90
0
10
0.7
400
2.00-
700,
20
30
40
-2.10
600
400
20
50
ㅎ 888 엉...
0.8
500-
W
0.9
2.20-1
2.30
-2.40
ENTHALPY, KJ/kg
2.50
500
400
Saturated Vapor
500
-20:
300
20
2.80
+A--
77
X
40
600
60
2.90
A
K
H
The
A
ai
i
TR
600
AN
15
+-+-₂
7.
80
100
4
3.00
S
p = 200 kg/m³
150
V
1
120-
+140
----
A
M
= 3.10 kJ/(kg.
160
·K)₂
S
700
100-
1
T
3.20
08
X
60
T = 180°C
3.30
700
1.
40
30
20
15
002.
10
8.0
6.0
4.0
3.0
2.0
1.5
1.0
0.80
0.60
0.40
0.30
0.20
800
20.
10.
8
6
2
1
0.8
0.6
0.4
0.2
0.1
0.08
0.06
0.04
0.02
0.01
800
Based on formulation of Tillner-Roth and Yokozeki (1997)
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