Single slit: a = 0.04 mm, l = 650 nm, l = 90 cm xm = _1.45cm_______(measured) xc = _1.46 cm_____ (calculated) %difference = 0.685 % θd = sin^-1(m λ/a) = sin-1 (1(650*10^-9)/(4*10-5)= 0.93o part 1: a)Validate that it was correct to use the small angle approximation for that activity: b)Describe the diffraction pattern for one-slit experiment: pleae answer part 1 questions a and b

Single slit: a = 0.04 mm, l = 650 nm, l = 90 cm xm = _1.45cm_______(measured) xc = _1.46 cm_____ (calculated) %difference = 0.685 % θd = sin^-1(m λ/a) = sin-1 (1(65010^-9)/(410-5)= 0.93o part 1: a)Validate that it was correct to use the small angle approximation for that activity: b)Describe the diffraction pattern for one-slit experiment: pleae answer part 1 questions a and b

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter36: Applications Of The Wave Model

Section: Chapter Questions

Problem 30PQ

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Concept explainers

Diffraction of light

In physics, the term diffraction is defined as the bending of light around the corners of the obstacle. As a light ray passes by an aperture, it bends around the edges or through slits, it spreads out through a narrow opening. The diffracted light will produce fringes of bright and dark or colored bands which are labeled as a diffraction pattern.

Question

Single slit:

a = 0.04 mm, l = 650 nm, l = 90 cm

x_m = _1.45cm_______(measured)

x_c = _1.46 cm_____ (calculated)
%difference = 0.685 %

θ_d = sin^-1(m λ/a) = sin^-1 (1(650*10^-9)/(4*10^-5)= 0.93^o

part 1:

a)Validate that it was correct to use the small angle approximation for that activity:

b)Describe the diffraction pattern for one-slit experiment:

pleae answer part 1 questions a and b

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