Since y; € {0, 1} (Bernoulli random variable), the joint density (pmf) of observing iid sample y = {₁,..., Yn} is E.g. the probability of observing y = (1, 0, 1) is f(y|B) = = f(y|B) = 1 [P(y; = 1|ß)]'¹ [P(y; = 0|ß)]¹-y₁ i-1 11 [P(y₁ = 1|B)]¹ [P(y₁ = 0[B)]° × [P(y₂ = 1 B)]° [P(y₂ = 0[B)]¹ x [P(y3 = 1 B)]¹ [P(y3 = 0|B)]⁰ P(y₁ = 1|B) P(y2 = 0 B)P(y3 = 1 B) exib Σ1 ex₁,B exß ex31ß 1 ex1 ex Σ; (18 β

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please teach this I do not no notations

- Since y; € {0, 1} (Bernoulli random variable), the joint density (pmf)
of observing iid sample y = {₁,..., Yn} is
f(y|B) = [P(y; = 1 B)] [P(y₁ = 0|ß)]¹-yi
E.g. the probability of observing y = (1, 0, 1) is
f(y|ß) =
=
=
[P(y₁ = 1|p)]¹ [P(y₁ = 0[ß)]° × [P(y2 = 1\ß)]° [P(y₂ = 0[B)]¹
x [P(y3 = 1 B)]¹ [P(y3 = 0|B)]⁰
P(y1 = 1 B) P(y2 = 0 B)P(y3 = 1 B)
exiß
Σ-1 ex₁, B
[₁-
ex21ß
Σ 1826
(18
ex31ß
Σ-1 ex;ß
Transcribed Image Text:- Since y; € {0, 1} (Bernoulli random variable), the joint density (pmf) of observing iid sample y = {₁,..., Yn} is f(y|B) = [P(y; = 1 B)] [P(y₁ = 0|ß)]¹-yi E.g. the probability of observing y = (1, 0, 1) is f(y|ß) = = = [P(y₁ = 1|p)]¹ [P(y₁ = 0[ß)]° × [P(y2 = 1\ß)]° [P(y₂ = 0[B)]¹ x [P(y3 = 1 B)]¹ [P(y3 = 0|B)]⁰ P(y1 = 1 B) P(y2 = 0 B)P(y3 = 1 B) exiß Σ-1 ex₁, B [₁- ex21ß Σ 1826 (18 ex31ß Σ-1 ex;ß
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