Since the feasible region is closed and bounded, we know that the maximum value will occur at ---Select--- . Thus, we test the corner points in the objective function. Corner f = 8x + 9y (0, 8) (4, 8) (6, 6) (9, 0) (0, 0) Thus, the maximum value of the function is which occurs at the point
Since the feasible region is closed and bounded, we know that the maximum value will occur at ---Select--- . Thus, we test the corner points in the objective function. Corner f = 8x + 9y (0, 8) (4, 8) (6, 6) (9, 0) (0, 0) Thus, the maximum value of the function is which occurs at the point
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The question is the step 2 portion.. included 2nd image to fill in gaps
Transcribed Image Text:Since the feasible region is closed and bounded, we know that the maximum value will occur at
---Select---
v. Thus, we test the corner points in the objective function.
Corner
f = 8x + 9y
(0, 8)
(4, 8)
(6, 6)
(9, 0)
(0, 0)
Thus, the maximum value of the function is
which occurs at the point
Transcribed Image Text:Solve the following linear programming problem. Restrict x 2 0 and y 2 0.
Maximize f = 8x + 9y subject to
x + y < 12
2x + y s 18
y < 8.
Step 1
We want to maximize the function f = 8x + 9y subject to
x + y < 12
2x + y < 18
y < 8
x2 0, y 2 0.
We start by graphing the feasible region given by the set of inequalities. Thus, we graph the equations
x + y = 12, 2x + y = 18, and y = 8 as solid
solid lines. Notice that the test point (0, 0) satisfies
%3D
satisfies all of the given inequalities, so the solution of the constraint system is the region on or
below
below the lines, in the first quadrant (since x > 0, y 0).
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