Since the cup itself can absorb energy, a separate experiment is needed to determine the heat capacity of the calorimeter. This is known as calibrating the calorimeter and the value determined is called the calorimeter constant. One way to do this is to use a common metal of known heat capacity. In the laboratory a student heats 90.57 grams of iron to 97.76 °C and then drops it into a cup containing 83.51 grams of water at 24.27 °C. She measures the final temperature to be 31.82 °C. Using the accepted value for the specific heat of iron (See the References tool), calculate the calorimeter constant. Calorimeter Constant = J/°C
Since the cup itself can absorb energy, a separate experiment is needed to determine the heat capacity of the calorimeter. This is known as calibrating the calorimeter and the value determined is called the calorimeter constant. One way to do this is to use a common metal of known heat capacity. In the laboratory a student heats 90.57 grams of iron to 97.76 °C and then drops it into a cup containing 83.51 grams of water at 24.27 °C. She measures the final temperature to be 31.82 °C. Using the accepted value for the specific heat of iron (See the References tool), calculate the calorimeter constant. Calorimeter Constant = J/°C
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![In the laboratory, a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific heat of a solid, or to measure the energy of a solution phase reaction.
![Image of a calorimeter setup. It includes a thermometer, stirring rod, water, and a metal sample within a cup.]
Since the cup itself can absorb energy, a separate experiment is needed to determine the heat capacity of the calorimeter. This is known as calibrating the calorimeter and the value determined is called the calorimeter constant.
One way to do this is to use a common metal of known heat capacity. In the laboratory, a student heats 90.57 grams of iron to 97.76 °C and then drops it into a cup containing 83.51 grams of water at 24.27 °C. She measures the final temperature to be 31.82 °C.
Using the accepted value for the specific heat of iron (see the References tool), calculate the calorimeter constant.
Calorimeter Constant = ____ J/°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F216d8975-823a-443e-8abc-06f056adfa09%2Ff1aed461-a9b3-42aa-880b-af8618712b50%2Fi1zk6i_processed.png&w=3840&q=75)
Transcribed Image Text:In the laboratory, a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific heat of a solid, or to measure the energy of a solution phase reaction.
![Image of a calorimeter setup. It includes a thermometer, stirring rod, water, and a metal sample within a cup.]
Since the cup itself can absorb energy, a separate experiment is needed to determine the heat capacity of the calorimeter. This is known as calibrating the calorimeter and the value determined is called the calorimeter constant.
One way to do this is to use a common metal of known heat capacity. In the laboratory, a student heats 90.57 grams of iron to 97.76 °C and then drops it into a cup containing 83.51 grams of water at 24.27 °C. She measures the final temperature to be 31.82 °C.
Using the accepted value for the specific heat of iron (see the References tool), calculate the calorimeter constant.
Calorimeter Constant = ____ J/°C

**Diagram Explanation:**
- A metal sample (platinum chunk) is submerged in water inside an insulated coffee cup calorimeter.
- The thermometer measures the temperature inside the cup.
- The stirring rod helps distribute the temperature evenly.
- The insulated cup prevents heat exchange with the surroundings, ensuring accurate measurement.
#### Constants and Problem Statement
The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.69 J/°C.
Using the accepted value for the specific heat of platinum (refer to the provided references), calculate the final temperature of the water. Assume that no heat is lost to the surroundings.
\[ T_{\text{final}} = \boxed{ \ \ \ \ \ \ } °C \]
**Key Points to Consider:**
- Mass of platinum: 18.92 grams.
- Initial temperature of platinum: 98.76 °C.
- Mass of water: 85.48 grams.
- Initial temperature of water: 20.46 °C.
- Calorimeter constant: 1.69 J/°C.
By using the principles of calorimetry and energy conservation, you can determine the final equilibrium temperature of the system.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F216d8975-823a-443e-8abc-06f056adfa09%2Ff1aed461-a9b3-42aa-880b-af8618712b50%2Ftlh6y7a_processed.png&w=3840&q=75)
Transcribed Image Text:### Using a Coffee Cup Calorimeter to Determine Specific Heat
In the laboratory, a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific heat of a solid or to measure the energy of a solution phase reaction.
#### Experiment Setup
In this example, a chunk of platinum weighing 18.92 grams and originally at 98.76 °C is dropped into an insulated cup containing 85.48 grams of water at 20.46 °C.
**Calorimeter Setup Diagram:**
The diagram illustrates the basic setup of a coffee cup calorimeter:
- **Thermometer:** Used to monitor the temperature inside the cup.
- **Stirring Rod:** Ensures even distribution of temperature within the cup.
- **Insulated Cup:** Contains the water and maintains the system's thermal isolation.
- **Metal Sample:** The platinum chunk is submerged in the water.

**Diagram Explanation:**
- A metal sample (platinum chunk) is submerged in water inside an insulated coffee cup calorimeter.
- The thermometer measures the temperature inside the cup.
- The stirring rod helps distribute the temperature evenly.
- The insulated cup prevents heat exchange with the surroundings, ensuring accurate measurement.
#### Constants and Problem Statement
The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.69 J/°C.
Using the accepted value for the specific heat of platinum (refer to the provided references), calculate the final temperature of the water. Assume that no heat is lost to the surroundings.
\[ T_{\text{final}} = \boxed{ \ \ \ \ \ \ } °C \]
**Key Points to Consider:**
- Mass of platinum: 18.92 grams.
- Initial temperature of platinum: 98.76 °C.
- Mass of water: 85.48 grams.
- Initial temperature of water: 20.46 °C.
- Calorimeter constant: 1.69 J/°C.
By using the principles of calorimetry and energy conservation, you can determine the final equilibrium temperature of the system.
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