Since molality is the number of moles of solute per kg of solvent, there is 15 g urea in 100 g naphthalene (or 150 g urea in 1000 g naphthalene). 150 = 2.5 mol mol = 60 g Therefore, the molar mass of urea is 60 g/mol." I do not understand where they got the 2.5 moles from in that example. Please explain to me how this was calculated.
Since molality is the number of moles of solute per kg of solvent, there is 15 g urea in 100 g naphthalene (or 150 g urea in 1000 g naphthalene). 150 = 2.5 mol mol = 60 g Therefore, the molar mass of urea is 60 g/mol." I do not understand where they got the 2.5 moles from in that example. Please explain to me how this was calculated.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question from my lab manual: "Calculate the molar mass of your unknown compound."
Here is the example given in the manual:
"Since molality is the number of moles of solute per kg of solvent, there is 15 g urea in 100 g naphthalene (or 150 g urea in 1000 g naphthalene).
150 = 2.5 mol
mol = 60 g
Therefore, the molar mass of urea is 60 g/mol."
I do not understand where they got the 2.5 moles from in that example. Please explain to me how this was calculated.
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