Since molality is the number of moles of solute per kg of solvent, there is 15 g urea in 100 g naphthalene (or 150 g urea in 1000 g naphthalene). 150 = 2.5 mol mol = 60 g Therefore, the molar mass of urea is 60 g/mol." I do not understand where they got the 2.5 moles from in that example. Please explain to me how this was calculated.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Question from my lab manual: "Calculate the molar mass of your unknown compound."

Here is the example given in the manual:

"Since molality is the number of moles of solute per kg of solvent, there is 15 g urea in 100 g naphthalene (or 150 g urea in 1000 g naphthalene).

150 = 2.5 mol

mol = 60 g

Therefore, the molar mass of urea is 60 g/mol."

I do not understand where they got the 2.5 moles from in that example. Please explain to me how this was calculated.

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