Since f'(x) > 0 when x << 0 (x * -1) and f'(x) < 0 when x > 0 (x 1), f is increasing on the intervals (--, -1) and and decreasing on the interväls (0, 1) and (F) The only critical number is x = 0. Since f' changes from positive to negative at is a local maximum by the First Derivative Test.

Q: Differentiate. f(x) = In f'(x) = .6 x 100 8

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Q: the derivative of E(q) is-(q*(q^2-1))^-1. what's its global maximum and global minimum. Thank you!

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Q: suppose f is a continuously differentiable function satisfying f(3)=6, and f'(3)=5. Find (f^-1)'(6)

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Q: Differentiate. f(x) = In f'(x) = X 6

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Q: Find f'(x) when 1. f'(x) 2. f'(x) 3. f'(x) 4. f'(x) 5. f'(x) f(x) = (²+²) ² 1 = = = = = 6. ƒ'(x) = =…

A: given,  f(x)=(x-2x+1)2

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Q: Assume that f is a polynomial and x = 10 is a critical number for f If f''(10) = -sqrt2 what do we…

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Q: Find f. f'(x) = 8x – 3/x*, x > 0, f(1) = 7 - f(x) =

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Q: Find f. f'(x) %3D 6х — 3/x*, х> 0, f(1) %3D 6

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Q: Find f '(x) given that f(x) = (2r³ + 3x²-5)(5x² - 2r+1) Show your work

A: We will use the product rule of differentiation to find the derivative

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