sin(A) = 48 csc(A) = cos(A) = + sec(A) = tan(A) = cot(A) = sin(B) = csc(B) = cos(B) = sec(B) = %3D %3D t tan(B) = cot(B) : sin(C) = |csc(C) = cos(C) = sec(C)
sin(A) = 48 csc(A) = cos(A) = + sec(A) = tan(A) = cot(A) = sin(B) = csc(B) = cos(B) = sec(B) = %3D %3D t tan(B) = cot(B) : sin(C) = |csc(C) = cos(C) = sec(C)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

Transcribed Image Text:Using the above information, compute the value of the sSix trig functions for each of the four angles.
48
sin(A) =
csc(A) =
cos(A) :
+ sec(A) =
tan(A) =
cot(A) =
sin(B) =
csc(B)
cos(B) =
sec(B) =
tan(B) =
cot(B)
sin(C) =
csc(C) =
cos(C) =
sec(C) =
tan(C) =
cot(C) =
sin(D) =
csc(D)
cos(D) =
sec(D)
tan(D) =
cot(D) =

Transcribed Image Text:Consider a ray drawn in the first quadrant as pictured below.
Let A be the angle between the positive x-axis and the ray pictured. If cos(A) = and sin(A) =
what is the point of intersection between the ray and the unit circle?
Reflect the ray across the y-axis into the 2nd quadrant. Let B be the angle between the positive x-axis and this new ray in the 2nd quadrant. What are the coordinates of intersection of this ray with angle B
and the unit circle?
Reflect the original ray across the origin (i.e, about the x-axis and then again about the y-axis) into the 3rd quadrant. Let C be the angle between the positive x-axis and this new ray in the 3rd quadrant.
What are the coordinates of intersection of this ray with angle C and the unit circle?
Reflect the original ray across the x-axis into the 4th quadrant. Let D be the angle between the positive x-axis and this new ray in the 4th quadrant. What are the coordinates of intersection of this ray with
angle D and the unit circle?
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