2) Show that:cos (0)sin (0)(6) (5) -(²Xp=Ypsincos (0)a)))||rp|| cos (0 - a)-||rp|| sin (0-a) P' (Xp'Yp')ӨXJaQa) 17 || sin(a)rY|rp|cos(a) P (XpYp)

This answer is given below.Explanation:

Answered: 2) Show that: cos (0) sin (0) (6) (5) -…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f' (3/2) = -sin(3pi/2) and f" (3л/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = cos(3pi/2) Use Q(x) to approximate cos(4.6). cos(4.6) cos(3pi/2)
4) Verify. cos²(x)[1 C. – tan²(x)] = cos(2x)
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b) 1+tanx 1–tanx = tan (x + 1)
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2) Show that: cos (0) sin (0) (6) (5) - (² Xp = Yp sin cos (0) a))) ||rp|| cos (0 - a) -||rp|| sin (0-a) P' (Xp'Yp') Ө X Ja Qa) 17 || sin(a) r Y|rp|cos(a) P (XpYp)