sin r 1 cos a , we should begin by cross-multiplying get rid of the fraction notation. To verify the identity 1+ cos z sin z If tan (2a) = 1, then a + na for any integer n. The first step in solving the equation cos = 1 is to apply the formula for the cosine of the difference of two angles. Cos a sin z In order to simplify 1- sin a a common denominator should first be found. Cos z V2 with b > 1 will always have less solutions than sin z because of the horizontal stretch by a factor of b. sin %3D cos a = 2 will have an extraneous solution. The equation tan a has no solution. The equation sin a = 1 has no solution.
sin r 1 cos a , we should begin by cross-multiplying get rid of the fraction notation. To verify the identity 1+ cos z sin z If tan (2a) = 1, then a + na for any integer n. The first step in solving the equation cos = 1 is to apply the formula for the cosine of the difference of two angles. Cos a sin z In order to simplify 1- sin a a common denominator should first be found. Cos z V2 with b > 1 will always have less solutions than sin z because of the horizontal stretch by a factor of b. sin %3D cos a = 2 will have an extraneous solution. The equation tan a has no solution. The equation sin a = 1 has no solution.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine whether each statement is true or false.
True
False
sin a
1- cos z
To verify the identity
,we should begin by cross-multiplying get rid of the fraction notation.
1+ cos a
sin x
If tan (22) = 1, then a =
+ na for any integer n.
The first step in solving the equation cos
= 1 is to apply the formula for the cosine of the difference of two angles.
cos a
1- sin z
sin a
In order to simplify
,a common denominator should first be found.
cos z
V2
with b > 1 will always have less solutions than sin z because of the horizontal stretch by a factor of b
sin
cos a = 2 will have an extraneous solution.
The equation tan a =
has no solution.
3
The equation sin a =
1
has no solution.
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