-1 sin ¹ (cos(-600°)) = 8. sin sec(sin-¹/3) = 9. sec 10. sin (cos ¹(-)) =

Q: secccos" (3))

A:

Q: -p² sin(w) cos?(w) – p cos² (») -p2 sin(4).

A:

Q: Find the value →21. csc (sec- 2) + cos (tan¬1 (– V3))

A:

Q: cos\theta =(1)/(3)and \theta  is in quadrant IV, then cos(\theta )/(2)

A:

Q: True or False sin(sin-1 0) = 0 and cos(cos-10) = 0.

A: Given:         sin(sin−10)=0  and cos(cos−10)=0

Q: sin(20) 0 = /-

A: When theta is between 0 to 360 degrees, then 2theta is between 0 to 720 degrees. We use sin inverse,…

Q: QUESTION 2 For cos2(xy) =- evaluate y when x = 1. 4 3 6. 3

A:

Q: Find the exact value of the expression whenever it is defined.

A: (a) sin-1-22 -π2≤x≤π2 sin x=-22 multiply and divide by 12 sin x =12  sin x = π4 sin-1-22=π4

Q: If sinx^2 =a/b find cos(90-x)

A: See the details solution in below I am consider  sin(x^2 )

Q: 2 cos "(\) tan-

A:

Q: Question 14 d (tanh -'(cosx)) dx A cschx B) -csCx C) -secx D cothx

A:

Q: 1.secB-cosB = tanB sin B 2.cotAcosA + sin A= cscA

A:

Q: if Sec X = 2 then tanx +Cos X =

A:

Q: cos x = sin 2x, x I SO 3.

A:

Q: Evalnate without using Calculator (^) Cos 2 () -9 (6) Sin 15°

A: a) We know that Therefore, we have

Q: (cos A + sin A)/(cos A - sin A) = (1+ sin(2A))/ cos(2A)

A:

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: 3 sin x y = [cot-1(품

A: Explanation of the answer is as follows

Q: V3 Tan" (-V3) Cos"(-1) 3. Sin 2 1. 2.

A:

Q: 4 sin 0-2 csc 0= 0 with 0 degrees

A: We use sin0=0 and csc0=1/sin0

Q: cot cos + tan sin (cosec+ sec )(1 - sin cos)

A: To prove that the given relation is true

Q: cos(A) cos(B)

A: Our Aim is to find the value of cos A cos B=?

Q: 5. sin³0 cos-20d0

A:

Q: sin x = csc 2x cos x cos 3x sec 2x

A:

Q: Sin'z cos' de

A: Given: ∫sin12x cos5x dx  ……1

Q: cot (0) csc (0) sec2 (0)

A:

Q: derivative its actually only cos^12 on the last idk why

A:

Q: sinx-1 10. Find cos x if --1. cosx a. -1 b. 2 с. 1 d. 0

A: Given: sin2 x-1cos x=-1

Q: to 11. If sin 18 0.309, determine the value of cos 72.

A: Answering question number 11 since 10th is already been correctly solved.

Q: sin[cos^-1(12/13)+tan^-1(4/3)]

A: Given: