(sin (2x)) dx = sin(2x)e-7x 7 sin(2x)e-72 7 Step 9 Hide steps Simplify. Hide steps + Simplify the answer. sin(2x)e 7 53 49 + 53 49 -7x -2(cos(2x)e -7x) 49 -2 (cos(2x)e-7) 49 Move the negative in front of the fraction. 53 49 2 cos(2x)e 49 + C -72 + C Multiply by the reciprocal of the fraction to A A

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Where did 53/49 came from? How did we came up with that specifically 53?
Step 8
Solving for
Je
-7x
S
е (sin (2x)) dx =
sin(2x)e
7
Step 9
sin(2x)e-7a
7
-72
Simplify.
Hide steps
-7x
e (sin (2x)) dx, we find that
Hide steps
+
Simplify the answer.
sin(2x) e
7
53
49
+
53
49
-7x
-2 (cos(2x)e-7x)
49
-2(cos(2x)e-7)
49
Move the negative in front of the fraction.
53
49
+ C
2 cos(2x)e-7z
49
+ C
Multiply by the reciprocal of the fraction to
A
A
Transcribed Image Text:Step 8 Solving for Je -7x S е (sin (2x)) dx = sin(2x)e 7 Step 9 sin(2x)e-7a 7 -72 Simplify. Hide steps -7x e (sin (2x)) dx, we find that Hide steps + Simplify the answer. sin(2x) e 7 53 49 + 53 49 -7x -2 (cos(2x)e-7x) 49 -2(cos(2x)e-7) 49 Move the negative in front of the fraction. 53 49 + C 2 cos(2x)e-7z 49 + C Multiply by the reciprocal of the fraction to A A
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