SIMULATION Electron Configurations: Box Notation IA SA 4p H 2A Не ЗА 4A SA 6A 7A 3d Li Be B C N F Ne 3p Na Mg 3B Al Si P CI Ar 4B 5B 6B 7B SB IB 2B 2p K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Fill All Clear Instructions: Add either a single electron or a pair of electrons to an orbital by clicking and dragging the arrow symbol onto the orbital box. To remove electrons from an orbital, click on the orbital box. Give the "box notation" (also called the "dash notation") electron configuration of N by filling electrons into the orbital spaces provided. Press Check when complete. Recheck Next (1 of 5) Show Approach

SIMULATION Electron Configurations: Box Notation IA SA 4p H 2A Не ЗА 4A SA 6A 7A 3d Li Be B C N F Ne 3p Na Mg 3B Al Si P CI Ar 4B 5B 6B 7B SB IB 2B 2p K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Fill All Clear Instructions: Add either a single electron or a pair of electrons to an orbital by clicking and dragging the arrow symbol onto the orbital box. To remove electrons from an orbital, click on the orbital box. Give the "box notation" (also called the "dash notation") electron configuration of N by filling electrons into the orbital spaces provided. Press Check when complete. Recheck Next (1 of 5) Show Approach

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

1A H2A 3A 4A 5A 6A Li Be Na Mg 3B 4B 5B 68 7B8B K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga B 1B 2B Al Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Si (2) The element with an electron configuration of 1s²2s²2p63s²3p64s23d104p¹ is in group 8A 7A He N OF NE P S Cl Ar Ge As Se Br Kr Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn ** Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr (1) The element with an electron configuration of 1s²2s²2p63s²3p64s²3d³ is in group and period and period
Fill in the blanks for the shorthand electron configuration as follows: Aluminum would be [Ne]3s^2 2p^1 Mn2+:[Ar] Mn4+:[Ar] Rh2+:[Kr] Ru3+:[kr] Check
For the following atoms, fill out the electron configuration and write out the arrow notation: Electron Configuration 1s 2s 2p 3s 3p 4s 3d Mg Ge Si Ca^2+ Cl^-
What is the electron configuration of Zr? Periodic table [Xe] 5s1 4d3 [Kr] 5s1 4d3 [Kr] 5s1 4f14 4d2 [Kr] 5s2 4d2
D. Give the quantum numbers for the last electron of each element given in Part II following the table below. Element 1 subshell N - 7 1s22s22p3 70 Ga,17⁰ Ar 1840 Sb,1122 112 AU79197 n main energy level 2 s=0 p=1 d=2 f=3 1 m₁ orbital -1 to 0 to +1 -1, 0, +1 +1 m₂ magnetic spin (+1/2, -1/2) +1/2
Following successive ionization energies (IE in kJ/mol) are for which atom? IE1 = 1085 IE2 = 2355 IE3 = 4620 IE4 = 6225 IE5 = 37830 hydrogan haun 2 H Не 4.000 1,009 hum fuorine beryum boon carton rogem ORygen neon 5 10 Li Be B N F Ne 2.001 611 sodum 9012 magnestm 12 15.999 sutur 16.998 20.100 son phongtone dne argon 11 13 14 15 16 17 18 Na Mg AI Si P S cI Ar 210 2.0 3074 22. potassm mnganese 25 cobat 27 32.00A seem 34 3545 brome 39.98 kryptn calm scandm vanam rkel opper 19 20 21 22 23 24 26 28 29 30 31 32 33 35 36 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br | Kr 1.00 241 ndum 37 rontm 38 tectnetm palaum 46 ca 48 dine 53 thertum she antinony on 39 40 41 42 43 44 45 47 49 50 51 52 54 Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te Хе 1260 sor ORI 79 1212 casm 55 La m 73 gtem 74 henm 75 pum 78 merry 80 han 81 Iad 82 pokm 84 on 86 bartum astane 56 57-70 71 72 76 77 83 85 Cs Ва Lu Hf Ta wRe Os Ir Pt Au Hg TI Pb Bi Po At Rn 1 22 memerum untum unu 109 200 0 203 andm 87 aborgum 106 tohum…
11
Which atoms or ions have the following electron configuration: 1s 2s 2p 3s-3p (select all the correct answers for full credit) O Ca2+ S2- N3- CI K+ Ar
3. A student was asked to write the electron configuration for a number of elements on an exam. Here is a sample of some of their answers: a) Ne s2 b) 1s²25³ c) [Kr] 4s1 Select any 2 of the answers above, and explain what is wrong. What element do you think they were describing? Write the correct electron configuration for that element.
Choose the incorrect statement when ml = 2. Group of answer choices The orbital can hold a maximum of 2 electrons. The value of l must be 2. A possible value of n could be 3. Another value of ml could be -2.
3.can you help me solve this
Explain the error in the following electron configuration for Sc, and provide the correct electron configuration. 1s² 2s² 2p 3s² 3p6 4s² 4d¹