Simplify the following Boolean expression. F(W,X, Y, Z) = !WX!Y!Z + WX!Y!Z + !WXY!Z + WXY!Z + !W!XZ + W!X!YZ+W!XYZ

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**Simplify the following Boolean expression.**

\[ F(W, X, Y, Z) = \overline{W}X\overline{Y}Z + WX\overline{Y}Z + \overline{W}XY\overline{Z} + WXY\overline{Z} + \overline{W}XZ + W\overline{X}YZ + W\overline{X}YZ \]

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\[ \text{[Input Box for Answer]} \]
Transcribed Image Text:**Simplify the following Boolean expression.** \[ F(W, X, Y, Z) = \overline{W}X\overline{Y}Z + WX\overline{Y}Z + \overline{W}XY\overline{Z} + WXY\overline{Z} + \overline{W}XZ + W\overline{X}YZ + W\overline{X}YZ \] --------------------------------------- \[ \text{[Input Box for Answer]} \]
Expert Solution
Step 1: To simplify the given Boolean expression F(W, X, Y, Z):

You can use Boolean algebra rules, including simplification using the distributive law and complementation. Here's the simplified expression:

F(W, X, Y, Z) = !WX!Y!Z + WX!Y!Z + !WXY!Z + WXY!Z + !W!XZ + W!X!YZ + W!XYZ

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