Simplify the expression. Write the expression without using negative exponents, if possible. 64 -2/3 27

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Simplifying the Expression

#### Problem Statement:
Simplify the expression. Write the expression without using negative exponents, if possible.

\[ \left( \frac{64}{27} \right)^{-\frac{2}{3}} \]

#### Steps to Simplify:

1. **Understand the Negative Exponent**:
   The expression \(\left( \frac{64}{27} \right)^{-\frac{2}{3}}\) contains a negative exponent. A negative exponent indicates the reciprocal of the base raised to the positive exponent:
   
   \[ \left( \frac{a}{b} \right)^{-n} = \left( \frac{b}{a} \right)^n \]

2. **Apply the Rule**:
   Convert the negative exponent to a positive exponent by taking the reciprocal of the base:
   
   \[ \left( \frac{64}{27} \right)^{-\frac{2}{3}} = \left( \frac{27}{64} \right)^{\frac{2}{3}} \]

3. **Simplify the Fraction**:
   Break down \( \left( \frac{27}{64} \right)^{\frac{2}{3}}\):
   \[
   \left( \frac{27}{64} \right)^{\frac{2}{3}} = \left( \frac{27^{\frac{1}{3}}}{64^{\frac{1}{3}}} \right)^2 
   \]

4. **Calculate the Cube Roots and Exponent**:
   \[
   27^{\frac{1}{3}} = 3 \quad \text{and} \quad 64^{\frac{1}{3}} = 4 
   \]
   Therefore,
   \[
   \left( \frac{27}{64} \right)^{\frac{2}{3}} = \left( \frac{3}{4} \right)^2 = \frac{9}{16}
   \]

#### Final Answer:
\[
\boxed{\frac{9}{16}}
\]

This method ensures that the expression is simplified without using negative exponents, as requested.
Transcribed Image Text:### Simplifying the Expression #### Problem Statement: Simplify the expression. Write the expression without using negative exponents, if possible. \[ \left( \frac{64}{27} \right)^{-\frac{2}{3}} \] #### Steps to Simplify: 1. **Understand the Negative Exponent**: The expression \(\left( \frac{64}{27} \right)^{-\frac{2}{3}}\) contains a negative exponent. A negative exponent indicates the reciprocal of the base raised to the positive exponent: \[ \left( \frac{a}{b} \right)^{-n} = \left( \frac{b}{a} \right)^n \] 2. **Apply the Rule**: Convert the negative exponent to a positive exponent by taking the reciprocal of the base: \[ \left( \frac{64}{27} \right)^{-\frac{2}{3}} = \left( \frac{27}{64} \right)^{\frac{2}{3}} \] 3. **Simplify the Fraction**: Break down \( \left( \frac{27}{64} \right)^{\frac{2}{3}}\): \[ \left( \frac{27}{64} \right)^{\frac{2}{3}} = \left( \frac{27^{\frac{1}{3}}}{64^{\frac{1}{3}}} \right)^2 \] 4. **Calculate the Cube Roots and Exponent**: \[ 27^{\frac{1}{3}} = 3 \quad \text{and} \quad 64^{\frac{1}{3}} = 4 \] Therefore, \[ \left( \frac{27}{64} \right)^{\frac{2}{3}} = \left( \frac{3}{4} \right)^2 = \frac{9}{16} \] #### Final Answer: \[ \boxed{\frac{9}{16}} \] This method ensures that the expression is simplified without using negative exponents, as requested.
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