In the simplified form of the exponent of a is Vab and the exponent of b is

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Topic Video
Question
**Topic: Simplifying Expressions Involving Exponents**

In the expression:

$$\frac{\sqrt{a} \sqrt[3]{b}}{\sqrt{a^5 b}},$$

when simplified, the exponent of \( a \) is [____] and the exponent of \( b \) is [____].

**Explanation:**
This problem involves simplifying an expression with roots and exponents. The given expression is a fraction with multiple root terms. To solve for the exponents of \( a \) and \( b \) once simplified, the rules of exponents and roots will be applied.

**Steps to Simplify:**

1. **Rewrite the Roots as Exponents:**
    - \(\sqrt{a}\) can be written as \(a^{1/2}\).
    - \(\sqrt[3]{b}\) can be written as \(b^{1/3}\).
    - \(\sqrt{a^5 b}\) can be written as \((a^5 b)^{1/2} = a^{5/2} b^{1/2}\).

2. **Combine the Exponent Terms:**
    - The numerator becomes \(a^{1/2} b^{1/3}\).
    - The denominator is \(a^{5/2} b^{1/2}\).

3. **Subtract Exponents in the Denominator from the Numerator:**
    - \(a\)'s exponent in the numerator is \(1/2\) and in the denominator is \(5/2\). 
    - \(1/2 - 5/2 = -2\).
    - \(b\)'s exponent in the numerator is \(1/3\) and in the denominator is \(1/2\).
    - \(1/3 - 1/2 = -1/6\).

4. **Final Simplified Exponents:**
    - The exponent of \(a\) is \(-2\).
    - The exponent of \(b\) is \(-1/6\).

Using this information, fill in the blanks in the provided format.

---

**Educational Objectives:**
- To strengthen understanding of exponent laws and transformations.
- To practice breaking down complex fraction expressions with roots.
- To reinforce simplification techniques involving exponents.
Transcribed Image Text:**Topic: Simplifying Expressions Involving Exponents** In the expression: $$\frac{\sqrt{a} \sqrt[3]{b}}{\sqrt{a^5 b}},$$ when simplified, the exponent of \( a \) is [____] and the exponent of \( b \) is [____]. **Explanation:** This problem involves simplifying an expression with roots and exponents. The given expression is a fraction with multiple root terms. To solve for the exponents of \( a \) and \( b \) once simplified, the rules of exponents and roots will be applied. **Steps to Simplify:** 1. **Rewrite the Roots as Exponents:** - \(\sqrt{a}\) can be written as \(a^{1/2}\). - \(\sqrt[3]{b}\) can be written as \(b^{1/3}\). - \(\sqrt{a^5 b}\) can be written as \((a^5 b)^{1/2} = a^{5/2} b^{1/2}\). 2. **Combine the Exponent Terms:** - The numerator becomes \(a^{1/2} b^{1/3}\). - The denominator is \(a^{5/2} b^{1/2}\). 3. **Subtract Exponents in the Denominator from the Numerator:** - \(a\)'s exponent in the numerator is \(1/2\) and in the denominator is \(5/2\). - \(1/2 - 5/2 = -2\). - \(b\)'s exponent in the numerator is \(1/3\) and in the denominator is \(1/2\). - \(1/3 - 1/2 = -1/6\). 4. **Final Simplified Exponents:** - The exponent of \(a\) is \(-2\). - The exponent of \(b\) is \(-1/6\). Using this information, fill in the blanks in the provided format. --- **Educational Objectives:** - To strengthen understanding of exponent laws and transformations. - To practice breaking down complex fraction expressions with roots. - To reinforce simplification techniques involving exponents.
Expert Solution
steps

Step by step

Solved in 3 steps with 4 images

Blurred answer
Knowledge Booster
Algebraic Operations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning