Simplify completely: -5√45x + 10√125x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Simplify completely:**

\[
-5\sqrt{45x} + 10\sqrt{125x}
\]

**Explanation:**

To simplify the expression, let's break down the square roots using factorization.

1. **Simplify \(\sqrt{45x}\):**
   - \(45x = 9 \times 5 \times x = 3^2 \times 5 \times x\)
   - So, \(\sqrt{45x} = \sqrt{3^2 \times 5 \times x} = 3\sqrt{5x}\)

2. **Simplify \(\sqrt{125x}\):**
   - \(125x = 25 \times 5 \times x = 5^2 \times 5 \times x\)
   - So, \(\sqrt{125x} = \sqrt{5^2 \times 5 \times x} = 5\sqrt{5x}\)

Now, substitute back into the original equation:

\[
-5(3\sqrt{5x}) + 10(5\sqrt{5x})
\]

Simplify further:

\[
-15\sqrt{5x} + 50\sqrt{5x} = 35\sqrt{5x}
\]

The completely simplified expression is:

\[
35\sqrt{5x}
\]
Transcribed Image Text:**Simplify completely:** \[ -5\sqrt{45x} + 10\sqrt{125x} \] **Explanation:** To simplify the expression, let's break down the square roots using factorization. 1. **Simplify \(\sqrt{45x}\):** - \(45x = 9 \times 5 \times x = 3^2 \times 5 \times x\) - So, \(\sqrt{45x} = \sqrt{3^2 \times 5 \times x} = 3\sqrt{5x}\) 2. **Simplify \(\sqrt{125x}\):** - \(125x = 25 \times 5 \times x = 5^2 \times 5 \times x\) - So, \(\sqrt{125x} = \sqrt{5^2 \times 5 \times x} = 5\sqrt{5x}\) Now, substitute back into the original equation: \[ -5(3\sqrt{5x}) + 10(5\sqrt{5x}) \] Simplify further: \[ -15\sqrt{5x} + 50\sqrt{5x} = 35\sqrt{5x} \] The completely simplified expression is: \[ 35\sqrt{5x} \]
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