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Simple Harmonic Motion At the equilibrium point x = 0 so, a=0 also. When the stretch is a maximum, a will be a maximum too. E= Umax = kA2 E= Kmax = momax E= Umax = kA? v=0 Umax v= 0 Fmax Fmax x=-A x= 0 x= +A Copyright © 2007 Pearson Prentice Hall, Inc. The velocity at the end points will be zero, and it is a maximum at the equilibrium point.

Simple Harmonic Motion At the equilibrium point x = 0 so, a=0 also. When the stretch is a maximum, a will be a maximum too. E= Umax = kA2 E= Kmax = momax E= Umax = kA? v=0 Umax v= 0 Fmax Fmax x=-A x= 0 x= +A Copyright © 2007 Pearson Prentice Hall, Inc. The velocity at the end points will be zero, and it is a maximum at the equilibrium point.

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Explain the diagram, especially the derivation of the energy formula in each motion of the mass.

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Simple Harmonic Motion At the equilibrium point x = 0 so, a= 0 also. When the stretch is a maximum, a will be a maximum too. E= Umax = KA? E = Kmax = m?max E= Umax = kA2 v= 0 Umax v = 0 Fmax max x= 0 Copyright © 2007 Pearson Prentice Hall, Inc. x = -A X = +A The velocity at the end points will be zero, and it is a maximum at the equilibrium point.
Transcribed Image Text:Simple Harmonic Motion At the equilibrium point x = 0 so, a= 0 also. When the stretch is a maximum, a will be a maximum too. E= Umax = KA? E = Kmax = m?max E= Umax = kA2 v= 0 Umax v = 0 Fmax max x= 0 Copyright © 2007 Pearson Prentice Hall, Inc. x = -A X = +A The velocity at the end points will be zero, and it is a maximum at the equilibrium point.
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