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Sign conventions: if the object, image, or focal point is on the reflective side of the mirror, its distance is positive, and negative otherwise. Magnification is if im upright negative otherwi

Sign conventions: if the object, image, or focal point is on the reflective side of the mirror, its distance is positive, and negative otherwise. Magnification is if im upright negative otherwi

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Problem Solving: Spherical Mirrors 1. Draw a ray diagram; the image is where the rays intersect. 2. Apply the mirror and magnification equations. 3. Sign conventions: if the object, image, or focal point is on the reflective side of the mirror, its distance is positive, and negative otherwise. Magnification is positive if image is upright, negative otherwise. 4. Check that your solution agrees with the ray diagram.
Transcribed Image Text:Problem Solving: Spherical Mirrors 1. Draw a ray diagram; the image is where the rays intersect. 2. Apply the mirror and magnification equations. 3. Sign conventions: if the object, image, or focal point is on the reflective side of the mirror, its distance is positive, and negative otherwise. Magnification is positive if image is upright, negative otherwise. 4. Check that your solution agrees with the ray diagram.
Step 1: (1) For upright image. B = obyeat ⇒ height = h A'B = image => height =-h' ( down right). distance from Pole of of image mirror = distance equation of magnitification (ii) AB= M = -h¹ negative soilimage is downright then negative. hene image height: =th' ( object height = h magnification = Thus if image = Step 2: (2) Downright image. positive. -4 (object distance) = - V supright) height of image height of object is cupright then = -x magnification will be h' h g = +ve (positive) magnification will be
Transcribed Image Text:Step 1: (1) For upright image. B = obyeat ⇒ height = h A'B = image => height =-h' ( down right). distance from Pole of of image mirror = distance equation of magnitification (ii) AB= M = -h¹ negative soilimage is downright then negative. hene image height: =th' ( object height = h magnification = Thus if image = Step 2: (2) Downright image. positive. -4 (object distance) = - V supright) height of image height of object is cupright then = -x magnification will be h' h g = +ve (positive) magnification will be
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