Shown on the drawing are the application of the different horizontal curves for a roadway project. GIVEN: Coordinates of Intersecting Points Length of Chord of the First Simple is 132.24 m Degree of Curve of the first curve of the compound Curve is 8 degrees The deflection angle from PC3 to Sta. 1+140 is 15°28' REQUIRED: 1. The azimuth and distance of the tangent lines. VERITY
Shown on the drawing are the application of the different horizontal curves for a roadway project. GIVEN: Coordinates of Intersecting Points Length of Chord of the First Simple is 132.24 m Degree of Curve of the first curve of the compound Curve is 8 degrees The deflection angle from PC3 to Sta. 1+140 is 15°28' REQUIRED: 1. The azimuth and distance of the tangent lines. VERITY
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:Shown on the drawing are the application of the different horizontal curves for a
roadway project.
GIVEN:
Coordinates of Intersecting Points
Length of Chord of the First Simple is 132.24 m
Degree of Curve of the first curve of the compound Curve is 8 degrees
The deflection angle from PC3 to Sta. 1+140 is 15°28'
REQUIRED:
1. The azimuth and distance of the tangent lines.
2. The Intersecting Angle (1), radius (R), tangent distance (T), Length of Curve (Lc) of
all the curves
3. The Stationing of PC, PT, PC2, PCC, PT2, PC3, PRC, PT3 and End of Project
Fill up your answer on the given table.
Show solutions.
IFICE
VESITY

Transcribed Image Text:PC1
PI1
0+000
Lct
PT1
R1
11
STATION NORTHINGS
EASTINGS
0+000
11475.55
8927.24
PC2
9291.91
9546.66
PI1
11478.80
P12
11179.37
R2
V1
PI3
10804.76
9282.44
Lc2
PI4
10512.37
9433.48
13
12
PCC
V1
11245.48
9490.41
PI2
V2
11074.50
9472.69
END
10203.85
9016.99
Lc3
R3
V2
LINE
AZIMUTH
DISTANCE
0-PI1
PI1-V1
V1-V2
PT2
V2-PI3
PI3-PI4
PI4-END
PC3
R4
CURVE
LC
1+140
PI3
1stCurve
2nd Curve
14
Lc4
3rd Curve
4th Curve
5th Curve
PRC
STATIONING
15
PC
PT
Lc5
PC2
P14
PCC
R5
PT2
PC3
PRC
PT3
PT3
END
END OF ROAD
---- ----
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