shown in the figure. Mercury fills a reservoir and is subject to standard atmospheric pressure. You place the bottom of the tube at the very top of the mercury level in the reservoir and require it to stay there at all times (so fluid is just shy of being displaced). What is the height in INCHES the mercury reaches inside the evacuated tube? This may be useful in understanding where atmospheric pressure readings in inches of Hg actually come from. (Note: This is not a “flow" problem, you simply are finding the maximum height that the mercury reaches up the evacuated tube when flow is zero. Also, for thermodynamics reasons, the mercury is not allowed to evaporate either). PHg = 13593 kg/m³, P = 1.013 x 105 Pa %3D atm , Show your work, making clear your use of energy density conservation!!

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P=0 at the top of the vertical tube.

### Determining the Height of Mercury in an Evacuated Tube

As shown in the figure below, mercury fills a reservoir and is subject to standard atmospheric pressure. The bottle of the tube is placed at the very top of the mercury level in the reservoir, ensuring it stays there at all times (so fluid is just shy of being displaced).

#### Question:
What is the height in **inches** the mercury reaches inside the evacuated tube? This calculation is essential for understanding where atmospheric pressure readings in inches of Hg come from. 

**Note:** This is not a "flow" problem; instead, you are finding the maximum height that the mercury reaches up the evacuated tube when flow is zero. Also, for thermodynamics reasons, the mercury is not allowed to evaporate.

Given:
\[ \rho_{Hg} = 13593 \, \text{kg/m}^3 \]
\[ P_{atm} = 1.013 \times 10^5 \, \text{Pa} \]

#### Instruction:
**Show your work, making clear your use of energy density conservation!**

#### Explanation of the Diagram:
The diagram illustrates a vertical evacuated tube partially filled with mercury, which is in turn part of a larger reservoir also containing mercury. The height to which the mercury will rise in this tube is what we need to calculate.

By using the concept of balance of pressure, we can determine the height \( h \) of the mercury column. The pressure exerted by the mercury column must equal atmospheric pressure:

\[ P_{atm} = \rho g h \]

Where:
- \( P_{atm} \) is atmospheric pressure
- \( \rho \) is the density of mercury
- \( g \) is the acceleration due to gravity (9.81 m/s\(^2\))
- \( h \) is the height of the mercury column

Rearranging for \( h \):

\[ h = \frac{P_{atm}}{{\rho g}} \]

By substituting the given values into the equation, we can calculate the height \( h \). Finally, convert this height from meters to inches for the final answer.
Transcribed Image Text:### Determining the Height of Mercury in an Evacuated Tube As shown in the figure below, mercury fills a reservoir and is subject to standard atmospheric pressure. The bottle of the tube is placed at the very top of the mercury level in the reservoir, ensuring it stays there at all times (so fluid is just shy of being displaced). #### Question: What is the height in **inches** the mercury reaches inside the evacuated tube? This calculation is essential for understanding where atmospheric pressure readings in inches of Hg come from. **Note:** This is not a "flow" problem; instead, you are finding the maximum height that the mercury reaches up the evacuated tube when flow is zero. Also, for thermodynamics reasons, the mercury is not allowed to evaporate. Given: \[ \rho_{Hg} = 13593 \, \text{kg/m}^3 \] \[ P_{atm} = 1.013 \times 10^5 \, \text{Pa} \] #### Instruction: **Show your work, making clear your use of energy density conservation!** #### Explanation of the Diagram: The diagram illustrates a vertical evacuated tube partially filled with mercury, which is in turn part of a larger reservoir also containing mercury. The height to which the mercury will rise in this tube is what we need to calculate. By using the concept of balance of pressure, we can determine the height \( h \) of the mercury column. The pressure exerted by the mercury column must equal atmospheric pressure: \[ P_{atm} = \rho g h \] Where: - \( P_{atm} \) is atmospheric pressure - \( \rho \) is the density of mercury - \( g \) is the acceleration due to gravity (9.81 m/s\(^2\)) - \( h \) is the height of the mercury column Rearranging for \( h \): \[ h = \frac{P_{atm}}{{\rho g}} \] By substituting the given values into the equation, we can calculate the height \( h \). Finally, convert this height from meters to inches for the final answer.
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