Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 8.76 Volts and is running at a frequency of f = 143000 Hz. The resistor has a resistance of R = 3460 , the capacitor has a capacitance of C = 4.53e-10 Farads, and the inductor has an inductance of L = 5.24e-03 Henries. Vps Write the FORMULA for the total impedance of the circuit Ztot = R Write the FORMULA for the phase of the total impedance of the circuit ztot Determine the numerical value of Ztot = Determine the numerical value of OZ tot = Determine the current through the circuit: I(PEAK) = I(RMS) = . Amps Amps Determine the voltage across the inductor: VL (PEAK) = VL(RMS) = Volts Volts 22 Volts Volts C degrees Determine the voltage across the capacitor: Vc(PEAK) = Vc(RMS) = If a second circuit were connected in parallel with the resistor, this circuit would be considered as:
Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 8.76 Volts and is running at a frequency of f = 143000 Hz. The resistor has a resistance of R = 3460 , the capacitor has a capacitance of C = 4.53e-10 Farads, and the inductor has an inductance of L = 5.24e-03 Henries. Vps Write the FORMULA for the total impedance of the circuit Ztot = R Write the FORMULA for the phase of the total impedance of the circuit ztot Determine the numerical value of Ztot = Determine the numerical value of OZ tot = Determine the current through the circuit: I(PEAK) = I(RMS) = . Amps Amps Determine the voltage across the inductor: VL (PEAK) = VL(RMS) = Volts Volts 22 Volts Volts C degrees Determine the voltage across the capacitor: Vc(PEAK) = Vc(RMS) = If a second circuit were connected in parallel with the resistor, this circuit would be considered as:
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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![Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 8.76 Volts and is
running at a frequency of f = 143000 Hz. The resistor has a resistance of R = 3460 , the capacitor has a capacitance of C = 4.53e-10 Farads, and the
inductor has an inductance of L = 5.24e-03 Henries.
Vps
Write the FORMULA for the total impedance of the circuit Ztot =
R
ww
Write the FORMULA for the phase of the total impedance of the circuit ztot
Determine the numerical value of Ztot =
Determine the numerical value of OZ tot
=
Determine the current through the circuit:
I(PEAK) =
I(RMS) =
.
Amps
Amps
Determine the voltage across the inductor:
VL (PEAK) =
VL(RMS) =
Volts
Volts
Determine the voltage across the capacitor:
Vc(PEAK) =
Vc(RMS) =
Volts
Volts
22
degrees
C
If a second circuit were connected in parallel with the resistor, this circuit would be considered as:
O a flux capacitor
O a phase conjugate deflector
O a low-pass filter
O a high-pass filter
O a capacitive switcher
O a radio tuner
NOTE: In your formulas, use variables R, w, L, and C. Do not use f.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7e9880ca-6e01-4524-bdb0-6786235f8792%2Fcbb037e8-d8cf-486f-963c-1d06c2a673c1%2Frwyx3iu_processed.png&w=3840&q=75)
Transcribed Image Text:Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 8.76 Volts and is
running at a frequency of f = 143000 Hz. The resistor has a resistance of R = 3460 , the capacitor has a capacitance of C = 4.53e-10 Farads, and the
inductor has an inductance of L = 5.24e-03 Henries.
Vps
Write the FORMULA for the total impedance of the circuit Ztot =
R
ww
Write the FORMULA for the phase of the total impedance of the circuit ztot
Determine the numerical value of Ztot =
Determine the numerical value of OZ tot
=
Determine the current through the circuit:
I(PEAK) =
I(RMS) =
.
Amps
Amps
Determine the voltage across the inductor:
VL (PEAK) =
VL(RMS) =
Volts
Volts
Determine the voltage across the capacitor:
Vc(PEAK) =
Vc(RMS) =
Volts
Volts
22
degrees
C
If a second circuit were connected in parallel with the resistor, this circuit would be considered as:
O a flux capacitor
O a phase conjugate deflector
O a low-pass filter
O a high-pass filter
O a capacitive switcher
O a radio tuner
NOTE: In your formulas, use variables R, w, L, and C. Do not use f.
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