Need help on figuring out question 6 a, b, and c 6. Shown below is the graph of the function r(0) = 2 + 4cose in rectangularcoordinatesr(0.6)A102Dohp0V(a) Using the information in the above graph, and without using a calculator, graph thesame function in polar coordinates using the polar coordinate grid. You should get acurve that looks very different from the one shown here.135 120-(-2)*10559290%COLZO1587200025.3025SPESTE DEE50/311he0-0°(2x, 6)0 8OC7%65Deemor Cleceroom Arthittingпа 100%0113A611Q 8 0(a) Using the information in the above graph, and without using a calculator, graph thesame function in polar coordinates using the polar coordinate grid. You should get acurve that looks very different from the one shown here.&7B119195.hp150°N210°ITC O Draction2 2018 fathemati20135 120 105-522 002+592(x,-2)135 120 105*890+ 75+012582903 / 4(b) Your graph should pass through the origin. At what value(s) of 8 does your graphpass through the origin?(c) Explain, in a few sentences, what causes a graph of a function in polar coordinatesto pass through the origin. How is this different from what makes a graph of afunction in rectangular coordinates pass through the origin?7. Using another polar coordinate grid, graph the function r(0) = 4 + 2sine. Whatdifference(s) do you notice between this graph and the one in the previous problem?How could we anticipate these differences just by looking at the formula for eachfunction?7596060+LOOK45(945°STE11. 1130.5SA3308-0°» TT 2✓0➜--A+11backspaceC

Given: rθ=2+4cosθ The graph in rectangular coordinate is shown as:From the above graph, we get the coordinates as θ,r 1. 0,6 2. π3,4 3. π2,2 4. 2π3,0 5. π,-2 6. 4π3,0 7. 3π2,2 8. 5π3,4 9. 2π,6 Plot these points on the polar coordinates, Now, draw the graph connecting these points in the order. So, the graph in polar is shown asUsing the graph, we can observe that the graph is passing through the origin at θ=2π3,4π3 Numerically, when graph passes through origin r=02+4cosθ=04cosθ=-2cosθ=-24cosθ=-12⇒θ=2π3,4π3 Therefore, θ=2π3,4π3The cause of a graph of a function in polar coordinates to pass through the origin is r=0. If value of r=0 for any value of theta in polar coordinates, the graph passes through the origin. In the rectangular coordinates, the graph of a function passes through the origin if both the values are 0 i.e., r=0, θ=0.

Math

Trigonometry

Shown below is the graph of the function r(0) = 2 + 4cose in rectangular coordinates r (0.6) 12 706 302 503 11he (2x, 6) 0 211 (a) Using the information in the above graph, and without using a calculator, graph the same function in polar coordinates using the polar coordinate grid. You should get a curve that looks very different from the one shown here.

Shown below is the graph of the function r(0) = 2 + 4cose in rectangular coordinates r (0.6) 12 706 302 503 11he (2x, 6) 0 211 (a) Using the information in the above graph, and without using a calculator, graph the same function in polar coordinates using the polar coordinate grid. You should get a curve that looks very different from the one shown here.

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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