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Show your work step by step please! Dont use others answers Will rate!! Using the final binary min heap on the picture, show the result of performing a dequeue( ) operation assuming a priority queue is implemented using a binary min heap.       BOX IN YOUR FINAL BINARY MIN HEAP.

Show your work step by step please! Dont use others answers Will rate!! Using the final binary min heap on the picture, show the result of performing a dequeue( ) operation assuming a priority queue is implemented using a binary min heap.       BOX IN YOUR FINAL BINARY MIN HEAP.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Show your work step by step please!

Dont use others answers

Will rate!!

Using the final binary min heap on the picture, show the result of performing a dequeue( ) operation assuming a priority queue is implemented using a binary min heap.

      BOX IN YOUR FINAL BINARY MIN HEAP.

This image illustrates a series of binary tree transformations, demonstrating the process of inserting values into a binary search tree (BST). Here’s a step-by-step explanation of each transformation: 1. **Initial Step**: The number 65 is inserted, forming the root node. 2. **Second Step**: 12 is inserted as the left child of 65. 3. **Subsequent Insertions**: - 73 is inserted as the right child of 65. - 36 is inserted as the right child of 12. - 30 is inserted as the left child of 36. - 55 is inserted as the right child of 36. 4. **Formation of the Complete BST**: - The tree is rearranged to maintain the BST properties, resulting in multiple subtrees and showing the order in which nodes are added and compared. 5. **Final Tree Configuration**: - 12 remains the root node, with 30 as its left child and 24 as its right child. - Further children are added to satisfy the BST conditions, where left children are smaller and right children are larger than their parent nodes. 6. **Inorder Traversal Result**: - The numbers in sorted order: 12, 30, 24, 65, 36, 73, 55, 92, displayed in a rectangular array at the bottom. This diagram effectively demonstrates how a binary search tree maintains order as nodes are inserted, emphasizing the systematic structure that supports efficient searching and sorting.
Transcribed Image Text:This image illustrates a series of binary tree transformations, demonstrating the process of inserting values into a binary search tree (BST). Here’s a step-by-step explanation of each transformation: 1. **Initial Step**: The number 65 is inserted, forming the root node. 2. **Second Step**: 12 is inserted as the left child of 65. 3. **Subsequent Insertions**: - 73 is inserted as the right child of 65. - 36 is inserted as the right child of 12. - 30 is inserted as the left child of 36. - 55 is inserted as the right child of 36. 4. **Formation of the Complete BST**: - The tree is rearranged to maintain the BST properties, resulting in multiple subtrees and showing the order in which nodes are added and compared. 5. **Final Tree Configuration**: - 12 remains the root node, with 30 as its left child and 24 as its right child. - Further children are added to satisfy the BST conditions, where left children are smaller and right children are larger than their parent nodes. 6. **Inorder Traversal Result**: - The numbers in sorted order: 12, 30, 24, 65, 36, 73, 55, 92, displayed in a rectangular array at the bottom. This diagram effectively demonstrates how a binary search tree maintains order as nodes are inserted, emphasizing the systematic structure that supports efficient searching and sorting.
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